1. Getting the amount of days of the defined date from 1/1/1960 2. We then multiply it by the number of seconds in a day (86,400) 3. Then subtract 315,569,260 seconds from the total. (We do this because there is a 10-year gap from 1/1/1960 and 1/1/1970. 315,569,260 ...
Note: In a Python program that obtains the UNIX epoch time from an input date value, subtract 315619200 from that value while processing the data. Functional window handling time Functional window deals with underlying integer directly to work with the Date and Stamp types. It provides multiple ...
If you base the calculation of the number of days to add or subtract based on the start of the following interval then the logic is exactly the same. So try doing it quarters. data quarter; do year=2021 to 2024 ; do qtr=1 to 4; length downame ...
Playing around with dates was my favorite because you get to do wacky things like calculating the number of days between two dates or extracting just the month from a date value. Time travel math! The proc steps were probably my favorite though. These are where you get to run different ...
Dates are stored as number of days. So just subtract the values. diff = date_event - date0 ; 0 Likes Reply PGStats Opal | Level 21 Re: Converting Dates Posted 06-14-2015 02:26 PM (1093 views) | In reply to Kenmar Or, if you want to free yourself of the underlying date...
Dates are stored as number of days. So just subtract the values. diff = date_event - date0 ; 0 Likes Reply PGStats Opal | Level 21 Re: Converting Dates Posted 06-14-2015 02:26 PM (1020 views) | In reply to Kenmar Or, if you want to free yourself of the underlying date...
Re: changing date Posted 02-12-2020 01:33 PM (1023 views) | In reply to Dhana18 So you want to subtract two weeks? When you need to shift a date by a given amount of a given interval, the intnx() function is the tool of choice. Maxims of Maximally Efficient SAS ProgrammersHow...
Make a dataset with PATIENT and INDEX_DATE and merge it with the existing dataset and then subtract the INDEX_DATE from the ADM_DATE and see if how many days difference there is. If you want to treat every admission as a new patient/index_date pair then you will need to use ...
Assuming that it represents the number of days since some date it is not hard to figure out what value you need add/subtract from it to get an actual date value. 2960 data x; 2961 have=40753 ; 2962 want='31MAY2011'd ; 2963 diff=want-have; 2964 put (_all_) (=comma12.); 2965...
I ask because from a second look I am now VERY sure that the formula is designed to calculate a number of months from a 4-digit integer that is written in a MMYY format: month = ( input(YEARS_OF_IMP,4.) - int( input(YEARS_OF_IMP,4.) / 100 ) * 100 /* subtract the left ...