Invalid third argument to function SUBSTR Posted 04-01-2019 11:29 AM (2523 views) I don't know how to revise the third argument that is producing the error message. It is referring to the line bolded below. Any suggestions much appreciated. if indexw(name_last,' AKA ') then do;...
By default, the characters in this list are removed from the source argument. If you specify the K modifier in the third argument, then only the characters in this list are kept in the result. Tip: You can add more characters to this list by using ...
46197 An "Invalid third argument to function SUBSTR.. " error appears when running load_named_lists.sas on UNIX 64-bit Enabled AIX, 64-bit Enabled Solaris, HP-UX IPF, Linux for x64, Microsoft Windows, Solaris for x64 46104 You can create and edit a financial effect even though your...
rounds the first argument to the nearest multiple of the second argument, or to the nearest integer when the second argument is omitted. ROUNDE rounds the first argument to the nearest multiple of the second argument, and returns an even multiple when the first argument is halfway between the...
INPUT function as in Sample 24591 using Date9, but it does not work. I get "Invalid argument to INPUT function at Line ### Column ##'. When I PUT the string data into the SASLOG it shows that it matches. The new data field using the INPUT function dusplays as missing... View mo...
The resulting character value will have leading blanks,which might cause problems when you perform an operation or function. P378、 Note If you specify an invalid date in the MDY function,SASassigns a missing value to the target variable. data dec.review98; set dec.review; ReviewDate=mdy(15...
I'm getting teh folloiwng error: Invalid third argument to function SUBSTR The variable cdcode is text and 14 characters long. Here's my code: data new; set old; length co $2 dist $5 sch $7; co=substr(cdcode, 1,2); dist=substr(cdcode, 3,7); sch=substr(cdcode,8,14); run...
'Invalid third argument to function SUBSTR at line 141 column 9'. Your code @ line 141 is: substr(D, 1, ':') = '01'; But the SUBSTR function uses a different format: SUBSTR(variable, position <, length>)=characters-to-replace I would suggest looking into TRANWRD instead of SUBSTR...
'Invalid third argument to function SUBSTR at line 141 column 9'. Your code @ line 141 is: substr(D, 1, ':') = '01'; But the SUBSTR function uses a different format: SUBSTR(variable, position <, length>)=characters-to-replace I would suggest looking into TRANWRD instead of SUBSTR...
NOTE: Invalid second argument to function SUBSTR at line 1 0 Likes Jagadishkatam Amethyst | Level 16 Re: how to split the below word Posted 11-13-2015 08:29 AM (2621 views) | In reply to vraj1 Sorry try this data want; set have; len=length(tm); ex=input(tranwrd(prxchange(...