3)Count:计算某特定字符、字符串在一个字符串中出现的个数。 Syntax:COUNT(string, substring <,modifiers>) Arguments string:specifies a character constant, variable, or expression in which substrings are to be counted. substring:i
ANYNAME Function Searches a character string for a character that is valid in a SAS variable name under VALIDVARNAME=V7, and returns the first position at which that character is found. ANYPRINT Function Searches a character string for a printable character, and returns the first position at whi...
where sql-expression is a character column, string (character constant), or expression(contain某些东西的列是字符型) procsql outobs=10;selectnamefromsasuser.frequentflyerswherenamecontains'ER'; quit; 3.3:IN Operatorto Select Values from a List column IN (constant-1 <, . . . constant-n>) co...
Count and display the number, type and position of special character present in the sample string (space is an exception hence it can be ignored). Create 3 additional variable Number - to display the unique number of special character present in the string Type – Print each special char...
COMPRESS Function Returns a character string with specified characters removed from the original string. COUNT Function Counts the number of times that a specified substring appears within a character string. COUNTC Function Counts the number of characters in a string that appear or do not appear...
@’characterstring’ 把指针移到数据行中字符串charaterstring之后的第一个非空格 列。 @charactervariable 首先确定字符变量所取值(即字符串)在输入行的位置,然后把指针 移到这个字符串之后的第一个非空格列。 @(characterexpression) 先确定字符表达式值的位置,然后移指针到其后第一个非空格 ...
If you have used repetitive INDEX and SUBSTR functions to determine how many times a “word” occurs in a character string, that task can also be accomplished more easily in Version 9. The COUNT function determines the number of times argument 2 occurs in argument 1. ...
Function COLLATE Function COMPARE Function COMPBL Function COMPGED Function COMPLEV Function COMPRESS Function COUNT Function COUNTC Function COUNTW Function DEQUOTE Function Removes matching quotation marks from a character string that begins with a quotation mark, and deletes all characters to the right...
You'd need to use the substring function within a loop and check each character, no time to check the syntax, but something like this my_string = "BBB12BBB"; do for i = 1 to length(my_string); if substr(my_string,i,1) = "B" then count+1; end; Another alternative:- first_co...
Compares two character variables, 0 if no difference COUNT() Counts occurance of text within a character variable SYMPUTX() SYMPUT() plus TRIM(), LEFT() and PUT() with BEST12. formatBeginner Paper Getting Familiar with SAS® Version 8.2 and 9.0 Enhancements, Sunil GuptaSAS...