intlengthOfLongestSubstring(string s){vector<int>last_seen(128,-1);intleft_boundary=-1,ret=-1;for(inti=0;ii32{letmutlast_seen:[i32;128]=[-1;128];letmutleft_boundary:i32=-1;letmutret:i32=0;letmutc:char=' ';for(i,ch)ins.char_indices(){left_boundary=std::cmp::max(left_bounda...
implSolution{pubfnlength_of_longest_substring(s:String)->i32{letmutmax_len=0;letmutstart=0;letmutchar_indices=std::collections::HashMap::new();for(i,c)ins.chars().enumerate(){ifletSome(&prev_idx)=char_indices.get(&c){ifprev_idx>=start{max_len=max_len.max(i-start);start=prev_id...
采用滑动窗口。 pubfnlength_of_longest_substring(s:String)->i32{usestd::collections::HashMap;ifs.len()==0{return0;}letmutmap=HashMap::with_capacity(s.len());lets=s.chars().collect::<Vec<_>>();letmutmax=0;letmutleft=0;s.iter().enumerate().for_each(|(index,char)|{ifletSome(l...
fnlength_of_longest_substring(s:String)->i32{// 初始化哈希map,key为字符类型(适用unicode字符处理)letmut rec=HashMap::<char,usize>::new();// 初始化最大长度,子串起始位置,子串临时长度let(mut max_len,mut start,mut tmp_len)=(0_i32,0_i32,0_i32);// 遍历字符串for(k,c)ins.chars().en...
Given a string, find the length of thelongest substringwithout repeating characters. Example Example 1: Input:“abcabcbb” Output:3 Explanation:The answer is "abc", with the length of 3. Example 2: Input:“bbbbb” Output:1Explanation:The answer is "b", with...
fn length_of_longest_substring(s:String) -> i32 { // 初始化哈希map,key为字符类型(适用unicode字符处理) let mut rec = HashMap::<char, usize>::new(); // 初始化最大长度,子串起始位置,子串临时长度 let (mut max_len, mut start, mut tmp_len) = (0_i32, 0_i32, 0_i32); ...
pub fn length_of_longest_substring(s: String) -> i32 { let s = s.as_bytes(); let mut index: [i32; 128] = [-1; 128]; let mut left = -1; let mut max_size = 0; for i in 0..s.len() { let k = s[i] as usize; ...
let s1 = String::from(); let len = calculate_length(&s1); // 借用 s1fn calculate_length(s: &String) -> usize { s.len() }生命周期: 生命周期是一个编译时概念，它使 Rust 能够确保引用在其整个使用期间都是有效的。fn longest<'a>(s1: &'astr, s2: &'astr) -> &'astr { if s1....
LeetCode 0873 Length of Longest Fibonacci Subsequence <Medium> <dynamic programming> <hash table> LeetCode 0097 Interleaving String <Medium> <dynamic programming> LeetCode 0115 Distinct Subsequences <Hard> <dynamic programming> LeetCode 0879 Profitable Schemes <Hard> <dynamic programming> LeetCode 0973...
Problem Given a string **s**, find the longest palindromic substring in **s**. You may assume that the maximum length of **s** is 1000. Example **Example 1:** **Input:** "babad" **Output:** "bab" **Note:** "aba" is also a valid answer. ...