how to run a java .class file with command line arguments from the consoleLogin
以下是修改后的代码示例: @ComponentpublicclassMyRunner{@AutowiredprivateAsyncServiceasyncService;@Overridepublicvoidrun(String...args)throwsException{asyncService.runAsync();}}@ServicepublicclassAsyncService{@AsyncpublicvoidrunAsync(){newThread(()->{System.out.println("Hello from a new thread!");}).st...
异常`CommandLineWrapper` is ill-suited for launching apps on Java 9+. If the run configuration uses "classpath file", please change it to "@argfile". Otherwise, please contact support.解决办法 异常显示 解决办法 1、在intellij idea的【Configurations】中设置【Shorten command line】选项为【@argfi...
publicclassMediocreExecJavac{publicstaticvoidmain(String args[]){try{Runtime rt=Runtime.getRuntime();Process proc=rt.exec("javac");InputStream stderr=proc.getErrorStream();InputStreamReader isr=newInputStreamReader(stderr);BufferedReader br=newBufferedReader(isr);String line=null;System.out.print...
importjava.io.BufferedReader; importjava.io.File; importjava.io.IOException; importjava.io.InputStream; importjava.io.InputStreamReader; publicclassRuntimeCMD { privatestaticProcess p; publicstaticvoidmain(String[] args)throwsIOException, InterruptedException { ...
publicclassTestRuntimeExec{publicstaticvoidmain(String[]args){try{Processprocess=Runtime.getRuntime().exec("ls");BufferedReaderreader=newBufferedReader(newInputStreamReader(process.getInputStream()));Stringline;while((line=reader.readLine())!=null){System.out.println(line);}}catch(IOExceptione){...
(Keep in mind that your class name should be the same as the file name) Compile thetesting.javafile on the terminal using thejavaccommand: $ javac testing.java Now, execute the Java program by calling its class name in the terminal: ...
【已解决】(class file version 53.0), this version of the Java Runtime only recognizes class file,程序员大本营,技术文章内容聚合第一站。
Option 1: Specify the dependencies while running the jar in the command line: java -cp <name-of-jar-with-extension>;<path-of-dependency-folder>/*;. <path-of-main-class> e.g. java -cp executable.jar;lib/*;. com.programmer.gate.HelloWorld Option 2: Specify the classpath of the ja...
JAR 清单:IntelliJ IDEA 将通过一个临时 classpath.jar 传递一个长 classpath。 原始 classpath 是在 清单 文件中作为 class-path 属性在 classpath.jar 中定义的。 通过这种方法,您将能够预览完整的命令行,而不仅仅是临时 classpath.jar 的类路径。 classpath file:IntelliJ IDEA 将把一个长 classpath 写入文...