postgres=# select split_part(c.a,',',1) as name, split_part(c.a,',',2) as age,row_number() over (partition by name) from (select regexp_split_to_table(info,';') as a from test1 where id in (1,2,4)) c; name | age | row_number ---+---+--- 张三| 12 | 1 张三...
import { createConnection, getConnection } from "typeorm"; async function getRowsWithRowNumber() { const connection = await createConnection({ type: "postgres", host: "your_host", port: 5432, username: "your_username", password: "your_password", database: "your_database", entities: [...
postgres=#createtablestudent(id serial,namecharactervarying,coursecharactervarying,scoreinteger);CREATETABLEpostgres=# postgres=# \d studentTable"public.student"Column|Type|Modifiers---+---+---id|integer|notnulldefaultnextval('student_id_seq'::regclass) name|charactervarying|course|charactervarying|score...
This tutorial works for PostgreSQL anywhere. If you need cloud Postgres,get the free plan on Neon. Summary: in this tutorial, you will learn how to use the PostgreSQLROW_NUMBER()function to assign a unique integer value to each row in a result set. ...
postgres=#select*,row_number()over(orderbyscoredesc)rnfromstudent; id|name|course|score|rn---+---+---+---+---2|周润发|数学|99|113|黎明|外语|95|26|周星驰|语文|91|314|黎明|物理|90|41|周润发|语文|89|58|周星驰|外语|88|65|周润发|化学|87|711|黎明|语文|85|810|周星驰|化学|83|97...
ROW_NUMBER()函数将针对SELECT语句返回的每一行，从1开始编号，赋予其连续的编号。在查询时应用了一个...
postgres=# select id,name,age,row_number() over(order by age) from test;id|name|age|row_number---+---+---+---3|张四|16|53|张三|14|33|张四|15|41|张三|12|12|张三|13|2(5rows) postgres=# select id,name,age,row_number() over(partition by name order by age) from test;id...
postgres=# select *,row_number() over(partition by course order by score desc)rn from student; id | name | course | score | rn ---+---+---+---+---5 | 周润发 | 化学 | 87 | 1 10 | 周星驰 | 化学 | 83 | 2 15 | 黎明 | 化学 | 78 | 3 13 | 黎明 | 外语 | 95 | ...
postgres=# select id,name,age,row_number() over(partition by name order by age) from test;id|name|age|row_number---+---+---+---1|张三|12|12|张三|13|23|张三|14|33|张四|15|13|张四|16|2(5rows) 1. 2. 3. 4. 5.
postgres=#selectsplit_part(c.a,',',1)asname, split_part(c.a,',',2)asage,row_number() over (partition by name)from(selectregexp_split_to_table(info,';')asafromtest1whereidin(1,2,4)) c; name| age |row_number---+---+---张三|12|1张三|13|2张三|14|3张十一|966|1张十一|...