If the later, I think it would be the function of the client application to retrieve the actual value from SQL Server and then display the value with 2 decimal places, even though it it possible to round the value in SQL Server. The reason is that if you need to do further calculations...
This query returns the gross price rounded to two decimal places: idprice_gross 1 2.90 2 1.51 3 0.47 Discussion: If you’d like to round a floating-point number to a specific number of decimal places in SQL, use the ROUND() function. The first argument of this function is the column ...
The datatype for ROUND is based on the original type (3,3). But rounding up to two decimal places gives you a result of 1.00, which is (3,2). A number with precision and scale of (3,2) cannot fit in (3,3) because there is no place to put the additional number to the left ...
The precision to which numeric_expression is to be rounded. When length is a positive number, numeric_expression is rounded to the number of decimal places specified by length. When length is a negative number, numeric_expression is rounded on the left side of the decimal point, as specified...
https://www.sqlservercentral.com/forums/topic/bankers-rounding-in-t-sql-like-math-round-in-net/page/4#post-4258087 This is the function we currently use, with some assumptions and simplifications. We only need to represent values below 1M and we always round to 2 decimal places. ...
Step 2:Populate the temporary table with random decimal values. Step 3:Run a SELECT statement to round each uniformly distributed random decimal value with both the SQL Server round function and the bankersround function. Optionally display the original decimal values and the two rounded sets of ...
Click to collapse [-]Server/client side Example (syntax 3) This example adds a command that outputs player's position rounded up to 2 decimal places addCommandHandler('showposition',function(ply) if localPlayer then local x,y,z = getElementPosition(localPlayer) x,y,z = math.round(x),...
select round(@number,@sf-1- floor(log10(abs(@number)))should do the trick !
I've used a SUM-formula which have given me an answer in cell B2, which is 1251,67. I want to round off so that the answer in cell B2 is 1252. How do I...
For d = 1, if n > k1 = k, then by Pigeonhole Principle, at least two students go to the same bus and they become good friends. Now suppose our claim is proven for d = i. To prove this for d = i + 1, we see that if we have n > ki +...