LeetCode算法题-Rotate Array(Java实现) 这是悦乐书的第184次更新,第186篇原创 01 看题和准备 今天介绍的是LeetCode算法题中Easy级别的第43题(顺位题号是189)。给定一个数组,将数组向右旋转k步,其中k为非负数。例如: 输入:[1,2,3,4,5,6,7],k = 3 输出:[5,6,7,1,2,3,4] 说明: 向右旋转1步...
Leetcode之Rotate Array 问题 andk=3,thearray[1,2,3,4,5,6,7] is rotatedto[5,6,7,1,2,3,4]. 思路分析: 这道题还是很常见的吧,只需要旋转三次就行了。但是,这道...问题描述:Rotateanarrayof n elementstotherightbyksteps. Note: Trytocome up as many solutions ...
swapArray(nums,0,numsLen-1);//反转整个数组swapArray(nums,0,k-1);//反转0到k-1索引,前k位的数组swapArray(nums,k,numsLen-1);//反转k到末尾索引,后剩余位数位的数组}privatevoidswapArray(int[] nums,intstart,intend){//反转函数inttemp;for(inti=start,j=end;i<j;i++,j--){ temp=nums[i...
Let’s say, we are required to write a JavaScript function that takes in an array and a number n and rotates the array by n elements For example: If the input array is − const arr = [12, 6, 43, 5, 7, 2, 5]; and number n is 3, Then the output should be − const ...
How to quickly rotate an array in Java using rotate()? Java中的Arrays类没有Rotate方法。我们可以使用Collections.rotate()来快速旋转数组。 // Java program to demonstrate rotation of array// with Collections.rotate()importjava.util.*;publicclassRotateDemo{publicstaticvoidmain(String[] args){// Let...
LeetCode 189: Rotate Array (Java) 题目: Rotate an array of n elements to the right by k steps. For example, with n = 7 and k = 3, the array [1,2,3,4,5,6,7] is rotated to [5,6,7,1,2,3,4]. 两种解法: 第一种是原地swap,记录下被挤掉的数再接着swap,需要一些时间举栗子...
leetcode-java文章分类后端开发 Rotate an array of n elements to the right by k steps. For example, with n = 7 and k = 3, the array [1,2,3,4,5,6,7] is rotated to [5,6,7,1,2,3,4]. Note: Try to come up as many solutions as you can, there are at least 3 different ...
Hint: Could you do it in-place with O(1 LeetCode编程练习 - Rotate Array学习心得 题目: Rotate an array ofn elements to the right byk steps. For example, withn = 7 andk = 3, the array[1,2,3,4,5,6,7] is rotated to[5,6,7,1,2,3,4]. 将n个元素的数组按k级旋转。例如,n...
You are given a target value to search. If found in the array return its index, otherwise return -1. You may assume no duplicate exists in the array. 最新更新请见:https://yanjia.me/zh/2019/01/... 二分法 复杂度 时间O(logN) 空间 O(1) ...
You can rotate the array using temp array in o(n). 1 2 3 4 5 6 7 8 9 10 11 12 13 14 15 16 17 18 19 20 public static int[] rotateExtraSpace(int[] nums, int k) { int n=nums.length; if(k > n) k=k%n; int[] result = new int[n]; for(int i=0; i < k; i...