arraydynamic✔️The array to rotate. rotate_countinteger✔️The number of positions that array elements will be rotated to the left. If the value is negative, the elements will be rotated to the right. Returns Dynamic array containing the same elements as the original array with each ...
For example, withn= 7 andk= 3, the array[1,2,3,4,5,6,7]is rotated to[5,6,7,1,2,3,4]. 1publicclassSolution {2publicvoidrotate(int[] nums,intk) {3intlength=nums.length;4if(k>length)5k=k%length;67intright[]=newint[k];8intleft[]=newint[length-k];9System.arraycopy(n...
reverse(nums,0, nums.length); }privatestaticvoidreverse(int[] nums,intbegin,intend) {intleft =begin;intright = end - 1;while(left <right) {//swapinttmp =nums[left]; nums[left]=nums[right]; nums[right]=tmp;++left;--right; } } } 方法2,reverse3次,分别是先将数组分为两段,前n-k...
/** * 重新加载刷新数据 */ private void reloadData() { removeAllViews(); for (int i = 0; i < mAdapter.getCount(); i++) { final int j = i; mCheckedTagArray.put(i, false); final View childView = mAdapter.getView(i, null, this); addView(childView, new MarginLayoutParams(Lay...
You are given a target value to search. If found in the array return its index, otherwise return -1. You may assume no duplicate exists in the array. 大致思路: 1.先判断nums[mid]是在左边还是右边; 2.如果在左边,1)如果target>nums[mid],left=mid+1; ...
This is an easy and reliable way to rotate in-place. You reverse the left side, next you reverse the right side, next you reverse the entire array. Upon completion the left and right block will be swapped. There's no known first publication, but it was prior to 1981.3 ┌─────...
类型:Array ; 默认:['tl', 'tm', 'tr', 'mr', 'ml', 'bl', 'bm', 'br', 'angle'] 对应 8 个缩放控件和旋转控件(不分顺序),传入空数组则不显示任何控件。 事件(Event) activated(pos, event) 点击选中元素参数:pos [Object] 位置信息;event [Object] 原生事件; ...
把整个2D array 看成一片一片的layer。每次rotate, 移动top, right, bot, left 各一个element 到下一个对应的layer上。也就是移动第一个top的东西到right第一个,移动right的第一个到bot的第一个,移动bot的第一个back to top的第一个。 然后移动top row的第二个到right的第二个,。。。
关键词:Array 关键点:利用k把数组分两半;reverse左右两边数组;reverse总数组 代码实现 classSolution{publicvoidrotate(int[]nums,intk){if(nums==null||nums.length==0||k%nums.length==0){return;}intturns=k%nums.length;intmiddle=nums.length-turns;reverse(nums,0,middle-1);// reverse left partrever...
Rotate Array (E) 题目 Given an array, rotate the array to the right byksteps, wherekis non-negative. Example 1: Input: [1,2,3,4,5,6,7] and k = 3 Output: [5,6,7,1,2,3,4] Explanation: rotate 1 steps to the right: [7,1,2,3,4,5,6] ...