Array: [ [ 0 1 2 ] [ 3 4 5 ] ] I want this array to be: [ [ 0 3 ] [ 1 4 ] [ 2 5 ] ] It is possible using for loop but that won't be a true numpy coding. python3numpyrotate-arrays 22nd May 2020, 6:34 AM ...
intarr[] = {1,2,3,4,5,6,7,8,9,10,11,12}; RotateArray ra =newRotateArray; ra.leftRotate(arr,8,12); for(inti =0; i < arr.length; i++) { System.out.print(arr[i] +" "); } } } Python 实现 defleftRotate(arr, k, n): k = k % n g_c_d = gcd(k, n) forii...
RotateArray ra = new RotateArray(); ra.leftRotate(arr, 8, 12); for (int i = 0; i < arr.length; i++) { System.out.print(arr[i] + " "); } } } Python 实现 def leftRotate(arr, k, n): k = k % n g_c_d = gcd(k, n) for i in range(g_c_d): temp = arr[i]...
class RotateArray { // 将数组 arr 向左旋转 k 个位置 void leftRotate(int arr[], int k, int n) { // 处理 k >= n 的情况,比如 k = 13, n = 12 k = k % n; int i, j, s, temp; // s = j + k; int gcd = gcd(k, n); for (i = 0; i < gcd; i++) { // 第...
代码(Python3) class Solution: def rotate(self, nums: List[int], k: int) -> None: """ Do not return anything, modify nums in-place instead. """ n: int = len(nums) # 计算最后有多少数字会被移动到数组开始 k %= n # 翻转整个数组 Solution.reverse(nums, 0, n - 1) # 翻转前 ...
图解:什么是旋转数组(Rotate Array)? 旋转数组 一文横扫数组基础知识 旋转数组分为左旋转和右旋转两类,力扣 189 题为右旋转的情况,今日分享的为左旋转。 给定一个数组,将数组中的元素向左旋转k个位置,其中k是非负数。 图 0-1 数组 arr 左旋转 k=2 个位置 原数组为arr[] = [1,2...
Rotate Array Rotate an array ofnelements to the right byksteps. For example, withn= 7 andk= 3, the array[1,2,3,4,5,6,7]is rotated to[5,6,7,1,2,3,4]. Note: Try to come up as many solutions as you can, there are at least 3 different ways to solve this problem. ...
Rotate an array of n elements to the right by k steps. For example, with n = 7 and k = 3, the array [1,2,3,4,5,6,7] is rotated to [5,6,7,1,2,3,4]. 1. Note: Try to come up as many solutions as you can, there are at least 3 different ways to solve this proble...
swapArray(nums,0,numsLen-1);//反转整个数组swapArray(nums,0,k-1);//反转0到k-1索引,前k位的数组swapArray(nums,k,numsLen-1);//反转k到末尾索引,后剩余位数位的数组 的顺序和参数即可,不再复现。 Python3(利用切片): classSolution:defrotate(self,nums:List[int],k:int)->None:""" ...
Python实现1: classSolution(object):defrotate(self,nums,k):""" :type nums: List[int] :type k: int :rtype: void Do not return anything, modify nums in-place instead. """n=len(nums)-1whilek>0:num=nums.pop()nums.insert(0,num)n-=1;k-=1# return numsdefrotate2(self,nums,k):...