Related problem:Reverse Words in a String II 解法1:一个最简单的想法就是每次将数组后移一步,一共循环k次。满足in-place,但是时间复杂度为O(k*n)。 classSolution {public:voidrotate(vector<int>& nums,intk) {intn =nums.size();if(n <2|| k <1)return;for(inti =1; i <= k; i++) {...
Question: http://leetcode.com/2010/04/rotating-array-in-place.html Rotate a one-dimensional array of n elements to the right by k steps. For instance, with n=7 and k=3, the array {a, b, c, d, e, f, g} is rotated to {e, f, g, a, b, c, d}...
class Solution(object): def rotate(self, nums, k): """ :type nums: List[int] :type k: int :rtype: void Do not return anything, modify nums in-place instead. """ k = k % len(nums) self.reversePart(nums, 0, len(nums)-k-1) self.reversePart(nums, len(nums)-k, len(nums)...
class Solution: def rotate(self, nums: List[int], k: int) -> None: """ Do not return anything, modify nums in-place instead. """ n: int = len(nums) # 计算最后有多少数字会被移动到数组开始 k %= n # 翻转整个数组 Solution.reverse(nums, 0, n - 1) # 翻转前 k 个数字 Soluti...
[LeetCode] Rotate Array / List Question: http://leetcode.com/2010/04/rotating-array-in-place.html Rotate a one-dimensional array of n elements to the right by k steps. For instance, with n=7 and k=3, the array {a, b, c, d, e, f, g} is rotated to {e, f, g, a, b,...
Could you do it in-place with O(1) extra space? Related problem: Reverse Words in a String II Code: 1.解法1:直接映射 时间复杂度O(N), 空间复杂度O(N) 1voidrotate(intnums[],intn,intk) {2//算法1:直接映射3int*p =newint[n];4for(inti =0; i < n; i++)5p[i] =nums[i];67...
Could you do it in-place with O(1) extra space? 要完成的函数: void rotate(vector<int>& nums, int k) 说明: 1、这道题给定一个vector,要求将这个vector最右边的元素调到最左边,重复这个动作k次,最终结果仍然存放在nums中。要求空间复杂度为O(1)。
title: 189. Rotate Array categories: - algorithm tags: - leetcode - algorithm - 第一遍取得最优解 题目描述 通过K步将一个有着n个元素的数组旋转到右侧。例如,给定n = 7和k = 3,数组[1,2,3,4,5,6,7]会被旋转成[5,6,7,1,2,3,4]。尽你可能尝试多种解决方案,这里至少存在3种不同的方式...
Given a rotated sorted array, recover it to sorted array in-place. 给定一个旋转排序数组,在原地恢复其排序。 【题目链接】 http://www.lintcode.com/en/problem/recover-rotated-sorted-array/ 【题目解析】 首先可以想到逐步移位,但是这种方法显然太浪费时间,不可取。下面介绍利器『三步翻转法』,以[4, ...
运行 AI代码解释 Given input matrix=[[1,2,3],[4,5,6],[7,8,9]],rotate the input matrix**in-place**such that it becomes:[[7,4,1],[8,5,2],[9,6,3]] Example 2: 代码语言:javascript 代码运行次数:0 运行 AI代码解释 Given input matrix=[[5,1,9,11],[2,4,8,10],[13,3,6...