LeetCode笔记:189. Rotate Array Rotate an array of n elements to the right by k steps. For example, with n = 7 and k = 3, the array [1,2,3,4,5,6,7] is rotated to [5,6,7,1,2,3,4]. 大意: 旋转一个有n个元素的数组,右移k步。 比如,n = 7,k = 3,数组 [1,2,3,4,...
public class RotateArray { //审题不仔细: k是从右边开始的 public void rotate(int[] nums, int k) { /*int n = nums.length; //自己的space:O(n) if(n==1 || k>=n) return ; int[] replace = new int[n]; for(int i=0;i < n-1-k;n++){ replace[i] = nums[k+i]; } for(...
Rotate Array Description: Rotate an array ofnelements to the right byksteps. For example, withn= 7 andk= 3, the array[1,2,3,4,5,6,7]is rotated to[5,6,7,1,2,3,4]. Note: Try to come up as many solutions as you can, there are at least 3 different ways to solve this pro...
https://leetcode.com/problems/rotate-array/ 题目描述: Rotate an array of n elements to the right by k steps. For example, with n = 7 and k = 3, the array [1,2,3,4,5,6,7] is rotated to [5,6,7,1,2,3,4]. Note: Try to come up as many solutions as you can, there ...
189. Rotate Array 从右边开始翻转数组 [抄题]: Rotate an array ofnelements to the right byksteps. For example, withn= 7 andk= 3, the array[1,2,3,4,5,6,7]is rotated to[5,6,7,1,2,3,4]. [暴力解法]: 时间分析: 空间分析:...
189. Rotate Array 旋转数组 Rotate an array of n elements to the right by k steps. For example, with n = 7 and k = 3, the array [1,2,3,4,5,6,7] is rotated to [5,6,7,1,2,3,4]. Note: Try to come up as many solutions as you can, th......
Rotate an array of n elements to the right by k steps. For example, with n = 7 and k = 3, the array [1,2,3,4,5,6,7] is rotated to [5,6,7,1,2,3,4]. Note:Try to come up as many solutions as you can, there are at least 3 different ways to solve this problem. [...
189.Rotate Array Rotate an array of n elements to the right by k steps. For example, with n = 7 and k = 3, the array [1,2,3,4,5,6,7] is rotated to [5,6,7,1,2,3,4]. 解题思路: 使用数组自带的pop()方法和unshift()方法把数组最后一个取出来加入到头部。
leetcode Merge sorted array 这道题采取的是从后往前填补的方式,如果还只剩下num1 就已经是完全排好序的如果nums2更加长然后还需要填充到num1里面 在这里插入图片描述...猜你喜欢LeetCode - Array - Easy - 26 思路: 这道题需要计算不重复的元素个数N,并且需要注意要将不重复的元素赋值给原数组的前N...
// Rotate Array// Time Complexity: O(n), Space Complexity: O(1)publicclassSolution{publicvoidrotate(int[]nums,intk){k%=nums.length;reverse(nums,0,nums.length-k);reverse(nums,nums.length-k,nums.length);reverse(nums,0,nums.length);}privatestaticvoidreverse(int[]nums,intbegin,intend){int...