Could you do it in-place with O(1) extra space? 算法 代码一 1 public void rotate(int[] nums, int k) { 2 int n = nums.length; 3 int temp; 4 k = k % n; 5 for (int i = 0; i < n / 2; i++) { 6 temp = nums[i]; 7 nums[i] = nums[n - 1 - i]; 8 nums[...
For example, withn= 7 andk= 3, the array[1,2,3,4,5,6,7]is rotated to[5,6,7,1,2,3,4]. Note: Try to come up as many solutions as you can, there are at least 3 different ways to solve this problem. [show hint] Hint: Could you do it in-place with O(1) extra space?
问题描述: Given an array of n integers where n > 1, nums, return an arrayoutput such thatoutput[i] is equal to the product of all the elements ofnums exceptnums[i]. Solve it without division and in O(n...Leetcode之Two Sum II - Input array is sorted 问题 问题描述: Given an ar...
Rotate an array of n elements to the right by k steps. For example, with n = 7 and k = 3, the array [1,2,3,4,5,6,7] is rotated to [5,6,7,1,2,3,4]. 将固定数组循环右移k步 注意:当k>numsSize的时候k = k % numsSize...leet...
Rotate an array of n elements to the right by k steps...array[left]= array[right]; array[right] = temp; left++; right--; } } void ...
* @return {void} Do not return anything, modify nums in-place instead. */ var rotate = function(nums, k) { let len = nums.length; k = k%len; let nums1 = nums.slice(len - k); nums.splice(-k, k); Array.prototype.unshift.apply(nums, nums1); ...
Given an array, rotate the array to the right byksteps, wherekis non-negative. Follow up: Try to come up as many solutions as you can, there are at least 3 different ways to solve this problem. Could you do it in-place with O(1) extra space?
LeetCode - Array - Easy - 26 思路: 这道题需要计算不重复的元素个数N,并且需要注意要将不重复的元素赋值给原数组的前N项。(虽然是统计个数,但最终验证是验证唯一的元素)。...HAL库ORE问题导致串口接收中断问题解决思路记录 一、问题描述 38400波特率下,1位起始位,1位停止位,无校验位,使用中断方式接收...
leetcode-189-Rotate Array Explanation:rotaterotate7,1, Example 2: 代码语言:javascript 代码运行次数:0 运行 AI代码解释 Input:[-1,-100,3,99]and k=2Output:[3,99,-1,-100]Explanation:rotate1steps to the right:[99,-1,-100,3]rotate2steps to the right:[3,99,-1,-100]...
then [rotated array](https://java2blog.com/search-element-in-sorted-and-rotated-array-java/ “rotated array”) will be {5, 6, 1, 2, 3, 4} Solution: There are multiple ways to solve this problem. Approach 1: Move each number by 1 place and do it k times. 1 2 3 4 5 6 ...