class Solution: # @return an integer def romanToInt(self, s): numerals = { "M": 1000, "D": 500, "C": 100, "L": 50, "X": 10, "V": 5, "I": 1 } sum=0 s=s[::-1] last=None for x in s: if last and numerals[x]<last: su
[LeetCode]题解(python):013-Roman to Integer 题目来源: https://leetcode.com/problems/roman-to-integer/ 题意分析: 这道题目和上一题目相反,是将罗马数字转化成阿拉伯数字。 题目思路: 只要知道罗马数字和阿拉伯数字之间是怎么转换的就可以了。先做一个字符和数值对应的字典,{'I':1,'V':5,'X':10,'...
[Leetcode][python]Roman to Integer/罗马数字转整数,题目大意将罗马数字转为整数解题思路与上一题不同,这一题可以使用dict。来自:Gitbook根据罗马数字的规则,只有在前面的字母比当前字母小的情况下要执行减法,其他情况只需要把罗马字母对应的数字直接相加即可。如果发
For example, two is written as II in Roman numeral, just two one’s added together. Twelve is written as, XII, which is simply X + II. The number twenty seven is written as XXVII, which is XX + V + II. Roman numerals are usually written largest to smallest from left to right. H...
letcode-13-roman to integer python: sum=0 d={'I':1,'V':5,'X':10,'L':50,'C':100,'D':500,'M':1000} for i in range(len(s)-1): if d[s[i]]<d[s[i+1]]: sum=sum-d.get(s[i]) else: sum+=d.get(s[i])
python3 根据罗马数字的计数规则, 模拟运算即可. classSolution:# @param{string} s # @return{integer} def romanToInt(self, s): ROMAN = {'I':1,'V':5,'X':10,'L':50,'C':100,'D':500,'M':1000}ifs =="":return0index = len(s) -2sum = ROMAN[s[-1]]whileindex >=0:ifROMAN...
master PythonAlgo/algorithms/strings/roman_to_int.py / Jump to Go to file 20 lines (16 sloc) 504 Bytes Raw Blame """ Given a roman numeral, convert it to an integer. Input is guaranteed to be within the range from 1 to 3999. """...
1. Convert an Integer to a Roman Numeral Write a Python class to convert an integer to a Roman numeral. Sample Solution-1: Python Code: classpy_solution:defint_to_Roman(self,num):val=[1000,900,500,400,100,90,50,40,10,9,5,4,1]syb=["M","CM","D","CD","C","XC","L","XL...
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Performance: Runtime: 52 ms, faster than 93.04% of Python3 online submissions for Integer to Roman. Memory Usage: 13.3 MB, less than 66.91% of Python3 online submissions for Integer to Roman.