13. Roman to Integer(罗马数字转整数) 今天开始第一次写LeetCode总结,只是想做一些总结方便自己,福利他人。 题目: Given a roman numeral, convert it to an integer. Input is guaranteed to be within the range from 1 to 3999. 给定一个罗马数字,将其转换成整数。
方法二:switch case,从左向右遍历 //与第一种方法基本相同,从左向右publicstaticintromanToInt1(String s) {char[] ss =s.toCharArray();intret = toNumber(ss[0]);for(inti = 1; i < ss.length; i++) {if(toNumber(ss[i - 1]) <toNumber(ss[i])) {//ret - toNumber(ss[i - 1]) =...
LeetCode13 - Roman to Integer Given a roman numeral, convert it to an integer. Input is guaranteed to be within the range from 1 to 3999. 解题思路: 罗马数字是符号和加操作的一个组合。他基于以下七个符号。 II is 2, and XIII is 13. 罗马数字没有0,所以 207是CCVII,1066 is MLXVI. 计数...
leetcode-013 Roman to Integer 将罗马数字转为整数 思路: (1)首先应该有个字典,存储罗马数字和阿拉伯数字之间的对应关系。 (2)遍历字符串,比较前后两个数的大小,如果后一个数比前一个数小,则加上后一个数,否则,减去后一个数。 为了防止数组索引越界,从后往前取,首先将最后一个数的值存进去,再一次和它...
LeetCode-Java-13. Roman to Integer 题目 Roman numerals are represented by seven different symbols: I, V, X, L, C, D and M. Symbol Value I 1 V 5 X 10 L 50 C 100 D 500 M 1000 For example, two is written as II in Roman numeral, just two one's added together. Twelve is ...
[Leetcode] Roman to Integer and Integer to Roman 罗马数阿拉伯数转换 Valid Roman Numeral 正则表达式 思路 首先我们要熟悉罗马数的表达方式。M是1000,D是500,C是100,L是50,X是10,V是5,I是1。验证字符串是否是罗马数,我们先看一下有效的罗马数是什么样的,假设该数字小于5000,从千位到个位依次拆解。
import java.util.Stack; public class RomanToInteger_13 { public static void main(String[] args) { System.out.println("Please input a roman numeral:"); @SuppressWarnings("resource") Scanner input = new Scanner(System.in); String s = input.next(); ...
问Integer to Roman“不兼容的类型: int无法转换为布尔型[在MainClass.java中]”EN根据罗马数字的规则...
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1 public String intToRoman(int num) { 2 int[] values={1000,900,500,400,100,90,50,40,10,9,5,4,1}; 3 String[] roman={"M","CM","