Peak value is I20I02 is the square of sum of different values. Hence, taking an average value (mean) I20/2I02/2 and then determining the square root I0/2–√I0/2 would give the RMS. It's example time: (I think you didn't ask for the derivation of RMS) Consider that both the...
You need to check the datasheet of the multimeter. Not all of them are capable of measuring the RMS value of an AC signal riding on a DC level. I would not take that for granted, even if it says “true RMS measurement”. Most manufacturers will make sure to write this capability...
The present invention requires only one sample can be calculated RMS alternating current power, and avoid the interference of the current rms calculations derivation process introduced. 本发明可靠性高,实时性强,故障判定速度快. The present invention, high reliability, real-time, fast failure ...