解析 1|b|j=(1000)TT⋅1/(5^t) 51:[i=(5000)Ti 8/1Li=(8000)+1/(5L) 3000∓1/(5L)=(3)RL 6000∓1/(5π)=(6)%L 4000=1/(52)=(4)▱ 3∓1/(52)=30001/(50) 2000÷2=2000 1|l_1|+200F⋅1/(52)= (1200)+1/(5π) 400F-1/(5π)+600F1/(52)=1)...