For each case, output the resulting ordered linked list. Each node occupies a line, and is printed in the same format as in the input. Sample Input: 00100 6 4 //第一行:链表的首地址add,结点个数n,每隔k个进行一次反转 00000 4 99999
1、用了c++函数库中的reverse() 2、直接用数组模拟内存
线性结构3 Reversing Linked List (25 分) Given a constant K and a singly linked list L, you are supposed to reverse the links of every K elements on L. For example, given L being 1→2→3→4→5→6, if K=3, then you must output 3→2→1→6→5→4; if K=4, you must output...
Given a constant K and a singly linked list L, you are supposed to reverse the links of every K elements on L. For example, given L being 1→2→3→4→5→6, if K=3, then you must output 3→2→1→6→5→4; if K=4, you must output 4→3→2→1→5→6. Input Specification:...
DS_Reversing Linked List 在PTA上刷DS的题目,有些问题和细节,放上来和大家分享和讨论 Given a constant K and a singly linked list L, you are supposed to reverse the links of every K elements on L. For example, given L being 1→2→3→4→5→6, if K=3, then you must output 3→2→1...
02-线性结构3 Reversing Linked List (25 分) Given a constant K and a singly linked list L, you are supposed to reverse the links of every K elements on L. For example, given Lbeing 1→2→3→4→5→6, if K=3, then you must output 3→2→1→6→5→4; if K=4, you must outpu...
Given a constant K and a singly linked list L, you are supposed to reverse the links of every K elements on L. For example, given L being 1→2→3→4→5→6, if K = 3, then you must output 3→2→1→6→5→4; if K = 4, you must output 4→3→2→1→5→6. ...
题目地址 https://pta.patest.cn/pta/test/16/exam/4/question/664 5-2 Reversing Linked List (25分) Given a constant KK and a singly linked list
题目来源:PTA02-线性结构2 Reversing Linked List (25分) Question:Given a constantKand a singly linked listL, you are supposed to reverse the links of everyKelements onL. For example, givenLbeing 1→2→3→4→5→6, ifK=3, then you must output 3→2→1→6→5→4; ifK=4, you must ...
pos=list[pos].Next; }if(k>1) { cnt=j/k;ints=0,r=j%k;while(cnt--) {for(i=s+k-1; i>s; i--) { tmp[i].Next=tmp[i-1].Addr; list[t++]=tmp[i]; }if(s+2*k<=j) { tmp[i].Next=tmp[s+2*k-1].Addr;