Linked List Cycle 题目链接 python代码实现: 实现思路: 快慢指针法。定义两个指针:快指针每次走一步;慢指针每次走两步。依次循环下去,如果链表存在环,那么快慢指针一定会有相等的时候。 为了便于理解,你可以想象在操场跑步的两个人,一个快一个慢,那么他们一定会相遇(无论他们的起始点是不是在操场)... 1052 Linked List Sor
1、用地址addr作为key存储链表节点,C语言由于没有哈希表,直接用addr作为数组的下标。 2、完成链表节点的存储后,需要找出链表的头节点,这里需要用next值作为key,存储本节点是否是其他节点的下一个节点:具体为,如果通过next能找到合法的链表节点,则这个合法的链表节点就不可能是头结点,循环给每一个节点打上标记 3、...
[PAT]02-线性结构2 Reversing Linked List (25分) Given a constantKK and a singly linked listLL, you are supposed to reverse the links of everyKK elements onLL. For example, givenLL being 1→2→3→4→5→6, ifK = 3K=3, then you must output 3→2→1→6→5→4; ifK = 4K=4, you...
02-线性结构3 Reversing Linked List (25 分) 因为发现有了adress,使用adress进行链表链接不方便,参考了网上使用数组的方法。 认真读题,每K个元素就要置逆一次 ...02-线性结构3 Reversing Linked List(25 分) 02-线性结构3 Reversing Linked List(25 分) 标签(空格分隔): 数据结构 算法竞赛 哇,今天这道...
2.6 线性结构之习题选讲:Reversing Linked List③是【浙江大学】数据结构(合149讲)陈越 何钦铭的第29集视频,该合集共计177集,视频收藏或关注UP主,及时了解更多相关视频内容。
代码: #include <cstdio> #include <cstring> #include <string> using namespace std; struct node { int val; int next; }; node a[100005]; int reverse(node *a, int head) { int answer = -1; while (head >= 0) { int next = a[head].next; ...
线性结构3 Reversing Linked List (25 分) Given a constant K and a singly linked list L, you are supposed to reverse the links of every K elements on L. For example, given L being 1→2→3→4→5→6, if K=3, then you must output 3→2→1→6→5→4; if K=4, you must output...
02-线性结构3 Reversing Linked List(25 point(s)) Given a constant K and a singly linked list L, you are supposed to reverse the links of every K elements on L. For example, given L being 1→2→3→4→5→6, if K=3, then you must output 3→2→1→6→5→4; if K=4, you ...
Given a constantK and a singly linked listL, you are supposed to reverse the links of everyK elements onL. For example, givenLbeing 1→2→3→4→5→6, ifK=3, then you must output 3→2→1→6→5→4; ifK=4, you must output 4→3→2→1→5→6. ...
Given a constant K and a singly linked list L, you are supposed to reverse the links of every K elements on L. For example, given L being 1→2→3→4→5→6, if K=3, then you must output 3→2→1→6→5→4; if K=4, you must output 4→3→2→1→5→6. ...