Reduce them to a single space in the reversed string. 提交了好多遍,终于成功了,使用了sstream来分割字符串,使用栈来存放分割之后的字符串,然后出栈就是逆序了。。 C++实现代码: #include<iostream>#include<string>#include<sstream>#include<stack>usingnamespacestd;classSolution {public:voidreverseWords(string...
#include<string>#include<algorithm>usingnamespacestd;classSolution{/** * @param s : A string * @return : A string */public:stringreverseWords(strings){stringss;//从后往前遍历sinti = s.length()-1;while(i>=0) {//跳过多余的空格while(i>=0&&s[i] ==' ') { i --; }if(i<0)bre...
word:栈,用于存放单词; 1#include<string>2#include<stack>3usingnamespacestd;456classSolution {7public:8voidreverseWords(string&s) {9stack<string>word;10inti =0;11boolflag =false;12intbeginpos =0;13while(i <=s.size()){14if(0==i){15if(s[i] !=''){16beginpos =0;17flag =true;18...
How about multiple spaces between two words? Reduce them to a single space in the reversed string. 提交了好多遍,终于成功了,使用了sstream来分割字符串,使用栈来存放分割之后的字符串,然后出栈就是逆序了。。 C++实现代码: AI检测代码解析 #include<iostream>#include<string>#include<sstream>#include<stack...
#include <stack> #include <string> #include <climits> #include <algorithm> #include <sstream> #include <functional> #include <bitset> #include <numeric> #include <cmath> using namespace std; class Solution { public: string reverseWords(string s) ...
usingSystem;usingSystem.LinqpublicclassSolution{publicstringReverseWords(strings){string[]array=s.Split(" ");if(array.Length>0){for(intai=0;ai<array.Length;ai++){char[]newarray=array[ai].ToCharArray();Array.Reverse(newarray);array[ai]=newstring(newarray);}}returnstring.Join(" ",array);}...
voiditerate_words(constchar* x){ We remember where this word has started at pointer x. constchar*a = x; We start looking for the start position of the next word (or rest of the sentence). And yes, if the string ends in the meantime, we don't need that position. We just set a...
2. Java Program to Reverse the Words of a String Whilereversing string content by words, the most natural way is to use aStringTokenizerand aStack. As you are aware thatStackis a class that implements an easy-to-uselast-in, first-out (LIFO)stack of objects. ...
0151-Reverse-Words-in-a-String 0153-Find-Minimum-in-Rotated-Sorted-Array 0155-Min-Stack 0159-Longest-Substring-with-At-Most-Two-Distinct-Characters 0160-Intersection-of-Two-Linked-Lists 0161-One-Edit-Distance 0167-Two-Sum-II-Input-array-is-sorted 0169-Majority-Element ...
string[] words = str.Split(' '); Array.Reverse(words); return string.Join(" ", words); } Abhinaba Basu [MSFT] August 2, 2007 Nope the .NET solution won't work as that is not constant space. E.g. your split will create 10 strings if there are 10 words on the stack. Even ...