Input: "a good example" Output: "example good a" Explanation: You need to reduce multiple spaces between two words to a single space in the reversed string. Note: A word is defined as a sequence of non-space characters. Input string may contain leading or trailing spaces. However, your ...
151. Reverse Words in a String Given an input string, reverse the string word by word. Example 1: Input: "the sky is blue" **Output: **"blue is sky the" Example 2: Input: " hello world! " **Output: **"world! hello" Explanation: Your reversed string should not contain leading...
A sequence of non-space characters constitutes a word. Could the input string contain leading or trailing spaces?Yes. However, your reversed string should not contain leading or trailing spaces. How about multiple spaces between two words? Reduce them to a single space in the reversed string. ...
publicStringreverseWords(Strings){Stack<String>stack=newStack<>();StringBuildertemp=newStringBuilder();s+=" ";for(inti=0;i<s.length();i++){if(s.charAt(i)==' '){if(temp.length()!=0){stack.push(temp.toString());temp=newStringBuilder();}}else{temp.append(s.charAt(i));}}if(stack...
Reverse Words in a String leetcode:https://oj.leetcode.com/problems/reverse-words-in-a-string 今天写了开题报告,有点不太想开那个报告了,没事又去A了一道ACM。这次A的是系统随机推荐的,刚看的时候以为是一个Easy类型的。感觉不太难 PS:一开始把题目理解错了,以为直接把所有字符Reverse。实际是将单词...
public static string ReverseWordsInString(string str) { string reverse = ReverseString(str); string temp = ""; foreach (string s in reverse.Split(' ')) { temp += ReverseString(s) + ' '; } return temp; } private static string ReverseString(string str) { char[] chars = str.ToCharA...
You need to reduce multiple spaces between two words to a single space in the reversed string. Follow up: For C programmers, try to solve itin-placeinO(1) extra space. 题目大意 给定一个字符串,逐个翻转字符串中的每个单词。 说明:
Yes. However, your reversed string should not contain leading or trailing spaces. How about multiple spaces between two words? Reduce them to a single space in the reversed string. fromcollectionsimportdequeclassSolution(object):defreverseWords(self,s):""":type s: str:rtype: str"""ifs==''...
Given an input string, reverse the string word by word. For example, Given s = "the sky is blue", return "blue is sky the". 注:该题目已有大神实现了,地址为 https://blog.csdn.net/lanxu_yy/article/details/38827845,但使用的是C++语言。
funcreverseWords(sstring)string{s=format(s)returnreverse(s)}funcformat(sstring)string{bs:=[]byte(s)end:=-1i:=0fori<len(bs){// 如果一个数字是字符,或者一个空格前是字符,则将该字符填入 end 里,否则ifbs[i]!=' '||(bs[i]==' '&&i!=0&&bs[i-1]!=' '){end++bs[end]=bs[i]}...