Given a string, you need to reverse the order of characters in each word within a sentence while still preserving whitespace and initial word order. Example 1: Input: "Let's take LeetCode contest"Output:"s'teL ekat edoCteeL tsetnoc" Note: In the string, each word is separated by single...
* @param {string} s * @return {string}*/varreverseWords =function(s) {varstr = s.split(" ");//截断成数组for(let i=0;i<str.length;i++){ str[i]= str[i].split("").reverse().join("");//把各子字符串截断为数组,再逆转,再拼成字符串}returnstr.join(" ");//再用空格分开字符...
Can you solve this real interview question? Reverse Words in a String III - Given a string s, reverse the order of characters in each word within a sentence while still preserving whitespace and initial word order. Example 1: Input: s = "Let's take
public String reverseWords(String s) { String[] table = s.split(" "); StringBuilder sb = new StringBuilder(); for (String str : table) { sb.append(reverse(str) + " "); } sb.deleteCharAt(sb.length() - 1); return sb.toString(); } private String reverse(String s) { StringBuilder...
557. Reverse Words in a String III class Solution { public: string reverseWords(string s) { istringstream temp(s); string text; string fin; bool flag = true; while (temp >> text) { if (!flag)fin += " "; else flag = false;...
public static string ReverseWordsInString(string str) { string reverse = ReverseString(str); string temp = ""; foreach (string s in reverse.Split(' ')) { temp += ReverseString(s) + ' '; } return temp; } private static string ReverseString(string str) { char[] chars = str.ToCharA...
Write a Python class that uses slicing to reverse the order of words in a given string. Write a Python class that implements a method to reverse each word's order and then reverse the word sequence. Write a Python class that uses recursion to reverse the order of words in a sentence and...
Note: In the string, each word is separated by single space and there will not be any extra space in the string. c语言实现 char*reverseWords(char*s){intstart=0;// char temp;intlen=strlen(s);//这个不放在外面就会超时for(inti=0;i<=len;i++){//注意这里的i<=strlen(s) 对于一个字符...
即:反转(first,last-1)区间内的元素顺序. 思路2:整个串s先反转一次,然后每个单词各自反转一次,类似于"矩阵转置等价于分块子矩阵转置加子矩阵间(位置)转置"的原理.但实现起来不简单. classSolution{//思路1public:stringreverseWords(string s){for(inti=0;i<s.length();i++){if(s[i]!=' '){//i指向...
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