Reverse Words in a String 翻转字符串里的单词(Python) 作者: 负雪明烛 id: fuxuemingzhu 个人博客:http://fuxuemingzhu.cn/目录 题目描述 题目大意 解题方法 日期题目地址:https://leetcode.com/problems/reverse-words-in-a-string/description/题目描述Given an input string, reverse the string word by ...
题意: Given an input string, reverse the string word by word. For example,Given s = "the sky is blue",return "blue is sky the". 解题思路:这题很能体现python处理字符串的强大功能。 代码: class Solution: # @param s, a string # @return a string def reverseWords(self, s): return "...
A sequence of non-space characters constitutes a word. Could the input string contain leading or trailing spaces? Yes. However, your reversed string should not contain leading or trailing spaces. How about multiple spaces between two words? Reduce them to a single space in the reversed string. ...
Given a string, you need to reverse the order of characters in each word within a sentence while still preserving whitespace and initial word order. Example 1: Input: "Let's take LeetCode contest" Output: "s'teL ekat edoCteeL tsetnoc" Note: In the string, each word is separated by si...
Leetcode: Reverse Words in a String 题目: Given an input string, reverse the string word by word. For example, Given s = “the sky is blue”, return “blue is sky the”. 思路一: 先休整下给定的字符串,去掉其中的多于一个的空格,就是使所有单词之间的空格都变成一个,然后去掉最后面的空格,...
Yes. However, your reversed string should not contain leading or trailing spaces. How about multiple spaces between two words? Reduce them to a single space in the reversed string. fromcollectionsimportdequeclassSolution(object):defreverseWords(self,s):""":type s: str:rtype: str"""ifs==''...
Python Code: # Define a function 'reverse_string_words' that takes a string 'text' as input.# The function splits the input text into lines, reverses the words within each line, and returns the result.defreverse_string_words(text):forlineintext.split('\n'):return(' '.join(line.split...
1classSolution:2#@param s, a string3#@return a string4defreverseWords(self, s):5ss = s.split("")6ss = filter(lambdax:x!="",ss)7l =len(ss)8foriinrange(l/2):9ss[i],ss[l-1-i] = ss[l-1-i],ss[i]10s = ("").join(ss)11returns ...
classSolution:defreverseWords(self,string:str)->str:words=[]cache=""string+=" "forsinstring:ifs!=" ":cache+=selifcache:words.append(cache)cache=""return" ".join(words[::-1]) Runtime: 44 ms, faster than 30.69% of Python3 online submissions for Reverse Words in a String. ...
Note: In the string, each word is separated by single space and there will not be any extra space in the string. c语言实现 char*reverseWords(char*s){intstart=0;// char temp;intlen=strlen(s);//这个不放在外面就会超时for(inti=0;i<=len;i++){//注意这里的i<=strlen(s) 对于一个字符...