publicclassSolution{publicstringReverseWords(strings){string[]array=s.Split(" ");stringnewString="";if(array.Length>0){for(intai=0;ai<array.Length;ai++){if(!string.IsNullOrEmpty(newString))newString=newString+=" ";char[]charArray=array[ai].ToCharArray();inti=0,j=charArray.Length-1;for...
// Importing necessary Java utilities.importjava.util.*;// Define a class named Main.publicclassMain{// Method to reverse words in a given string.publicstaticStringWordsInReverse(Stringstr1){// Create a StringBuilder object and reverse the entire string.StringBuildersb=newStringBuilder(str1);Str...
void reverseWords(string &s) { s = removeDuplicateSpace(s); int begin = 0; int end = 0; while(end < s.size()){ if(s[end] == ' '){ swapString(s, begin, end - 1); begin = end+1; end = begin; } else{ end++; } } swapString(s, begin, end - 1)...
151. Reverse Words in a String Given an input string, reverse the string word by word. Example 1: Input: "the sky is blue" **Output: **"blue is sky the" Example 2: Input: " hello world! " **Output: **"world! hello" Explanation: Your reversed string should not contain leading...
Reverse Words in a String Given an input string, reverse the string word by word. For example, Given s = "the sky is blue", return "blue is sky the". click to show clarification. Clarification: What constitutes a word? A sequence of non-space characters constitutes a word. ...
Reverse Words in a String(翻转字符串) 给定一个字符串,逐个翻转字符串中的每个单词。 Given s = "the sky is blue", return "blue is sky the". 单词的构成:无空格字母构成一个单词 输入字符串是否包括前导或者尾随空格?可以包括,但是反转后的字符不能包括...
链接https://leetcode-cn.com/problems/reverse-words-in-a-string-iii/ 耗时 解题:7 min 题解:4 min 题意 给定一个字符串,你需要反转字符串中每个单词的字符顺序,同时仍保留空格和单词的初始顺序。 提示:在字符串中,每个单词由单个空格分隔,并且字符串中不会有任何额外的空格。 思路 模拟题意,详见代码。
Given s = "the sky is blue", return "blue is sky the". 1 public class Solution_Reserse { 2 public String reverseWords(String str){ 3 String str_result = ""; 4 String str_word = ""; 5 char array_src[] = str.toCharArray(); ...
Given s = “the sky is blue”, return “blue is sky the”. Update (2015-02-12): For C programmers: Try to solve it in-place in O(1) space. public class Solution { public String reverseWords(String s) { if (s == null || s.length() == 0) { ...
Given an input string,reverse the string word by word.For example,Given s="the sky is blue",return"blue is sky the". 比较基础的一个题,拿到这个题,我的第一想法是利用vector来存每一个子串,然后在输出,这是一个比较简单的思路,此外,还有第二个思路,就是对所有的字符反转,然后在针对每一个子串反转...