Given theheadof a singly linked list, reverse the list, and return the reversed list. 给定一个单链表的头节点,将链表反转并返回反转后的链表。 解题思路 多指针题目,headNode指示当前的头部,也就是需要返回的结果;nextNode是添加新节点的next节点,维护该值可以减少查询的次数;currentNode是我们目前需要处理的...
publicListNodereverseList(ListNodehead){ListNodepre=null,cur=head,next=null;while(cur!=null){next=cur.next;cur.next=pre;pre=cur;cur=next;}returnpre;} 二、递归法 递归法和迭代法思路是一样的。 代码如下: publicListNodereverseList(ListNode head){if(head==null||head.next==null){returnhead;}Lis...
At first, we need to look at the basic function utilities in the driver code implemented to demonstrate the example. The linked list node is a simple struct with a single string data object and a pointer to the next node. We also have the addNewNode function that takes two arguments, ...
代码如下: public ListNode reverseList(ListNode head){ if(head == null || head.next == null){ return head; } ListNode n = reverseList(head.next); head.next.next = head; head.next = null; return n; } 只是注意两个地方: 如果head是空或者遍历到最后节点的时候,应该返回head。 代码5,6行。
[输入量]:空: 正常情况:特大:特小:程序里处理到的特殊情况:异常情况(不合法不合理的输入): [画图]: https://www.geeksforgeeks.org/reverse-a-linked-list/ 1)将列表分为两部分-第一个节点和 链接列表的其余部分。 2)呼叫反向链接列表的其余部分。
Reverse a linked list from position m to n. Do it in-place and in one-pass.For example:Given1->2->3->4->5->NULL, m = 2 and n = 4,return1->4->3->2->5->NULL.Note:Given m, n satisfy the following condition:1 ≤ m≤ n≤ length of list....
A linked list can be reversed either iteratively or recursively. Could you implement both? 题意 将一个链表翻转,有递归和非递归两种方法。 思路 递归 首先判断链表的长度,如果只有一项或为空,直接返回链表即可。 否则,先假装第k+1项及之后所有项都采用递归进行翻转,链表即为n1->n2->……->nk->nk+1-<...
The number of nodes in the list is the range[0, 5000]. -5000 <= Node.val <= 5000 Follow up:A linked list can be reversed either iteratively or recursively. Could you implement both? Accepted 0 Submissions 0 Acceptance Rate 0%
·nt!PsGetNextProcessß Based on the function name here, it appears that we were trying to traverse the linked list of active processes on the system. ·nt!ExpGetProcessInformationß NtQuerySystemInformation() called this function. Based on the function name Get...
LeetCode上第206号问题:Reverse Linked List 反转一个单链表。 示例: 输入: 1->2->3->4->5->NULL 输出: 5->4->3->2->1->NULL 进阶: 你可以迭代或递归地反转链表。你能否用两种方法解决这道题? 思路 设置三个节点pre、cur、next (1)每次查看cur节点是否为NULL,如果是,则结束循环,获得结果 ...