Out[23]: '瓜南小个一是你' 参考stackflow上的答案。 原理是:This is extended slice syntax. It works by doing [begin:end:step] - by leaving begin and end off and specifying a step of -1, it reverses a string. 切片介绍:切片操作符中的第一个数(
Initializing the JIT engine with a stack: >>> jitter=machine.jitter(loc_db,jit_type='python') >>> jitter.init_stack() Add the shellcode in an arbitrary memory location: >>> run_addr=0x40000000>>>frommiasm.jitter.cstsimportPAGE_READ,PAGE_WRITE>>> jitter.vm.add_memory_page(run_addr,...
This Blog provides a comprehensive guide to creating prime numbers, perfect numbers, and reverse numbers in Python. Learn More about Python Numbers!
EXIST_REVERSE_DIRECTORY:如果app曾经被调试过就是✅,从没被调试过就是❌ stephen@Mac:~/hooker$ python3 hooker.py hooker Let's enjoy reverse engineering together---PID APP IDENTIFIER EXIST_REVERSE_DIRECTORY0 全球上网 com.miui.virtualsim ❌0 爱奇艺 com.qiyi.video ❌0 红手指云手机 com.redfing...
No-IP Dynamic Update Client (DUC) 2.1.9 - Local IP Address Stack Overflow 漏洞简析 stack漏洞dynamicipoverflow poc(exp可以查看底部链接,不过那个exp不好使,因为好像便宜不对,而且返回地址是写死的) 用户1423082 2024/12/31 760 PC微信逆向:实现自动添加好友分享名片 微信 在我的成品 WeChatRobot 里面实现了...
(&self->data); vec_capacity = self->vec_capacity; retstr->buf = heap_buf->buf; retstr->p_buf_capacity = &heap_buf->buf_capacity; retstr->vec_capacity = vec_capacity; } else // capacity <= 0x100 { stack_buf = smallvec::SmallVecData<A>::inline_mut(&self->data); buf = _...
stack<char> words; stack<char> sentence; for (size_t i = 0; i < length; i++) { //如果不为空格,压入words栈中 if (s[i] != ' ') words.push(s[i]); //如果是空格且words不为空的话,将words中的字符压入sentence栈中且在sentence后面添加空额 ...
That's more like it! We see a normal function prelude (saving intra-function registers to the stack), some processing, and a function return. But GDB warns us about illegal instruction parameters (0x2000016c). When looking at the listing, we see that GDB indicates the usage of a ...
stack<int> cache; for(int i = 0 ; i < tokens.size(); i++){ if(tokens[i] == "+" || tokens[i] == "-" || tokens[i] == "*" || tokens[i] == "/"){ int num2 = cache.top(); cache.pop(); int num1 = cache.top(); cache.pop(); cache.push(calculate...
intn1 = stack.pop(), n2 = stack.pop(); stack.push(n2 / n1); break; default: stack.push(Integer.parseInt(a[i])); } } returnstack.pop(); } Python: 1 2 3 4 5 6 7 8 9 10 11 12 13 14 15 16 17 18 19 20 21 # Time: O(n) ...