D. Reverse Sort Sum(思维+构造) Problem - D - Codeforcescodeforces.com/contest/1659/problem/D 题意: 有一个长度为n的只包含0和1的a数组,分别对该数组的前i位排序(1≤i≤n),可以构成n个长度为n的01数组,将n个数组的第i位相加可以得到一个b数组,现在给你b数组让你求出原始的a数组。 思路: 对...
打Codeforces Round #782 (Div. 2)时遇到的有趣的题,记录一下 D. Reverse Sort Sum 题意 对于一个长度为 n 的01数列 A ,我们定义 Bi 为将A 的前i 位排序后得到的数列,如 A=[0,1,1,0,1,0] 那么 B1=[0,1,1,0,1,0] B2=[0,1,1,0,1,0] B3=[0,1,1,0,1,0] B4=[0,0,...
,f(n,A). Let CC be the array obtained by taking the element-wise sum of B1,B2,…,BnB1,B2,…,Bn. For example, let A=[0,1,0,1]A=[0,1,0,1]. Then we have B1=[0,1,0,1]B1=[0,1,0,1], B2=[0,1,0,1]B2=[0,1,0,1], B3=[0,0,1,1]B3=[0,0,1,1], B4=[...
sort(a + L, a + R + 1); }; int main() { while (cin >> n) { memset(sum, 0, sizeof(sum)); int tot = 1 << n; for (int i = 1; i <= tot; i++){ scanf("%I64d", a + i); } build(n, 1, tot); int m, q; cin >> m; for (int i = 0; i < m; i+...
B:http://codeforces.com/contest/1360/problem/B 题意: 将n个数分成两组,要求一组的最大值减去另一组的最小值的绝对值最小。 解析: 直接sort然后找最小间距 #include<iostream> #include<cstdio> #include<algorithm> #include<cstring> ...
sort(a+l,a+r+1); }intmain() { scanf("%d",&n);inty=(1<<n); Riep(y)scanf("%d",a+i); dfs(1,y,n);intq,x; scanf("%d",&q);while(q--) { scanf("%d",&x);while(x) { swap(sum[x][0],sum[x][1]); x--; ...
codeforces 414C C. Mashmokh and Reverse Operation(归并排序求逆序对),题目链接:C.MashmokhandReverseOperationtimelimitpertest4secondsmemorylimitpertest512megabytesinputstandardinputoutputstandardoutput
codeforces1025 hackforces + fstforces A 很明显当有一个字母出现次数>1时即合法 $n = 1$的情况需要特判 #include<cstdio> #include<ve ... Sublime的用法 一.首先安装插件 1.安装Package Control,这是为了安装其他插件做基础,它可以方便我们下载其他插件 (1).按Ctrl+`调出console(注:避免热键冲突) (...
B:http://codeforces.com/contest/1360/problem/B题意:将n个数分成两组,要求一组的最大值减去另一组的最小值的绝对值最小。解析:直接sort然后找最小间距#include<iostream> #include<cstdio> #include<algorithm> #include<cstring> using namespace std; typedef long long ll; const int maxn=1e3+10; ...
文章标签codeforcesc语言#includeci逆序文章分类办公效率 B. Sort the Array time limit per test memory limit per test input output aconsisting ofndistinct ais too small. You want a bigger array! Your friends agree to give you a bigger array, but only if you are able to answer the following qu...