importjava.util.Scanner;classReverseNumberWhile{publicstaticvoidmain(Stringargs[]){intnum=0;intreversenum=0;System.out.println("Input your number and press enter: ");//This statement will capture the user inputScannerin=newScanner(System.in);//Captured input would be stored in number numnum=i...
# Define a function to find the reverse of a given number using a while loopreverse_number<-function(number){# Initialize variablesreverse<-0# Iterate until the number becomes 0while(number!=0){# Extract the last digit of the numberdigit<-number%%10# Append the digit to the reverse numbe...
cin>>number;//takes valuefromuserwhile(number!=0){reverse_number=reverse_number*10;reverse_number=reverse_number+number%10;number=number/10;}cout<<"Reverse of entered number is:";cout<<reverse_number;//printreverse valuereturn0;} Output: Example 2: Find Reverse Number in C++ Using Recursion...
In this Python tutorial, you learned how toreverse a list in Pythonusing slicing, while, and for loops. You also learned about logic and how reverse operations can be performed. You may like to read: How to reverse a number in Python Python List reverse() method [With Examples]...
out.printf("Enter number: "); num = X.nextInt(); tmp = num; while (tmp > 0) { tmp = tmp / 10; len = len + 1; } res = reverseNumber(num, len); System.out.printf("Reversed number is: " + res); } } OutputEnter number: 7634 Reversed number is: 4367 ...
Program for Palindrome number in Python A palindrome number is a number or a string that when reversed, remains unaltered. num = int(input("Enter a number")) temp = num rvrs = 0 while(num>0): dig = num%10 rvrs = rvrs*10+dig num = num//10 if(temp == rev): print("The number...
System; public class ReverseExample { public static void Main(string[] args) { int n, reverse=0, rem; Console.Write("Enter a number: "); n= int.Parse(Console.ReadLine()); while(n!=0) { rem=n%10; reverse=reverse*10+rem; n/=10; } Console.Write("Reversed Number: "+reverse); ...
So next, let’s translate this idea into Kotlin code using the division operator ‘/‘ and the modulus operator ‘%‘: fun reverseNumber(number: Int): Int { var n = number var result = 0 while (n > 0) { result = 10 * result + n % 10 n = n / 10 } return result } Next...
using namespace std; int main() { int n; cin>>n; string s; while(n--) { cin>>s; int begin = 0,end,i,j; if(s[0] == '-')begin = 1; while(s[begin] == '0')begin++; end = s.size()-1; while(s[end] == '0')end--; ...
/* PHP program to reverse a number without using function */ $num = 2039; $revnum = 0; while ($num != 0) { $revnum = $revnum * 10 + $num % 10; //below cast is essential to round remainder towards zero $num = (int)($num / 10); } echo "Reverse number: $revnum\n";...