Leetcode 25. Reverse Nodes in k-Group 题目描述:就是在前一题翻转2个链表节点的题目上变成翻转k个位置。 题目链接:Leetcode25.ReverseNodesink-Group代码如下 参考链接 数据结构面试题oj练习 题oj链接:https://leetcode-cn.com/problems/remove-linked-list-elements/description/ 总结: 做这道题,一定要注意返...
# Definition for singly-linked list.# class ListNode:# def __init__(self, x):# self.val = x# self.next = NoneclassSolution:defreverseKGroup(self, head, k):""" :type head: ListNode :type k: int :rtype: ListNode """has_no_or_one_node = (notheadornothead.next)ifhas_no_or_...
}publicListNode reverseK(ListNode head,intk) {if(head ==null|| head.next ==null|| k == 1) {returnhead; } ListNode dummy=newListNode(0); dummy.next=head; ListNode cur=dummy;//不足k个node直接返回for(inti = 0; i < k; i++) { cur=cur.next;if(cur ==null) {returndummy.next;...
while (pre != tail) { ListNode temp = node.next; node.next = pre; pre = node; node = temp; } } }
next) if has_no_or_one_node or k == 1: return head dummy = ListNode(-1) dummy.next = head begin = dummy i = 0 while head: i += 1 if i % k == 0: begin = self._reverse(begin, head.next) head = begin.next else: head = head.next return dummy.next def _reverse(self,...
packageleetcode// ListNode definetypeListNode=structures.ListNode/** * Definition for singly-linked list. * type ListNode struct { * Val int * Next *ListNode * } */funcreverseKGroup(head*ListNode,kint)*ListNode{node:=headfori:=0;i<k;i++{ifnode==nil{returnhead}node=node.Next}newHead:...
25. Reverse Nodes in k-Group Given a linked list, reverse the nodes of a linked list k at a time and return its modified list. k is a positive integer and is less than or equal to the length of the linked list. If the number of nodes is not a multiple of k then left-out node...
Reverse Nodes in k-Group - LeetCode (如有侵权,请联系作者删除) Hard 题意 给定一个链表和一个数字k,要求返回一个链表。使得链表当中每k个元素倒叙。 注意: 只能允许线性的额外空间,即是空间复杂度必须在O(n) 不能修改node的值,只能修改node
25 Reverse Nodes in k-Group class Solution { public: ListNode* reverseKGroup(ListNode* head, int k) { bool flag = false; bool chk = false; ListNode *p; ListNode *temp; ListNode *firstNode; ListNode *idx= new ListNode(-1); while (!flag) {...
Leetcode 25. Reverse Nodes in k-Group 题目描述:就是在前一题翻转2个链表节点的题目上变成翻转k个位置。 题目链接:Leetcode 25.ReverseNodes in k-Group 代码如下 参考链接 832 翻转图像 代码: 二维数组,用了双重for循环去解决,水平翻转用了reverse(),反转用了 a = !a; ...