为了记录NodeM的前驱节点,我们新建一个虚拟节点,使得该节点的next域指向head; 代码语言:javascript 代码运行次数:0 运行 AI代码解释 ListNode pre=newListNode(0); 我们并不移动pre这个节点,因为在移动的过程中会改变pre存储的地址,我们再新建一个Mpre; 代码语言:javascript 代码运行次数:0 运行 AI代码解释 ListNode ...
return1->4->3->2->5->NULL. Note: Given m, n satisfy the following condition: 1 ≤ m ≤ n ≤ length of list. 将指定区间内的链表逆置, 原本写的版本太丑陋了,贴一个根据别人思路写出来的简洁版本。 代码语言:javascript 代码运行次数:0 /** * Definition for singly-linked list. * struct L...
reverse linked list / 反转链表 functionListNode(val, next) {this.val= (val ===undefined?0: val)this.next= (next ===undefined?null: next) }consthead =newListNode(1,2); head.next=newListNode(2,3);// 递归varreverseList =function(head) {if(head ==null|| head.next==null) {returnhe...
1/**2* Definition for singly-linked list.3* function ListNode(val) {4* this.val = val;5* this.next = null;6* }7*/8/**9* @param {ListNode} head10* @return {ListNode}11*/12varreverseList =function(head) {13if(!head || !head.next){14returnhead;15}1617varres =newListNode(-...
javascript 单向链表反转 reverse 部分反转 leetcode: https://leetcode.com/problems/reverse-linked-list/ /** * Definition for singly-linked list. * function ListNode(val) { * this.val = val; * this.next = null; * } */ /** * @param {ListNode} head...
Reverse a singly linked list. 反转链表,我这里是采用头插法来实现反转链表。 代码如下: /*class ListNode { int val; ListNode next; ListNode(int x) { val = x; } } */ public class Solution { public ListNode reverseList(ListNode head) ...
Program to reverse a linked list in java publicclassLinkedList{//head object of class node will point to the//head of the linked listNode head;//class node to create a node with data and//next node (pointing to node)publicstaticclassNode{intdata;Node next;Node(intdata,Node next){this....
=NULL){//loop till the end of linked list next=cur->next;//next = cur->next to store the rest of the list; cur->next=prev;//change the direction of linked list prev=cur; //update prev cur=next; //update cur } head=prev; //update head return head; //return head } void ...
The linked list node is a simplestructwith a singlestringdata object and a pointer to the next node. We also have theaddNewNodefunction that takes two arguments,Node*and a reference to thestring. TheaddNewNodefunction is invoked multiple times in themainroutine to construct a new list object...
Reverse Linked List II 题目大意 翻转指定位置的链表 解题思路 将中间的执行翻转,再将前后接上 代码 迭代 代码语言:javascript 代码运行次数:0 运行 AI代码解释 classSolution(object):# 迭代 defreverseBetween(self,head,m,n):""":type head:ListNode:type m:int:type n:int:rtype:ListNode""" ...