解法二(Java) /*** Definition for singly-linked list. * public class ListNode { * int val; * ListNode next; * ListNode(int x) { val = x; } * }*/classSolution {publicListNode reverseList(ListNode head) {if(head ==n
Output: 5->4->3->2->1->NULL /*** Definition for singly-linked list. * public class ListNode { * int val; * ListNode next; * ListNode(int x) { val = x; } * }*/classSolution {publicListNode reverseList(ListNode head) { ListNode curr=head; ListNode preNode=null;//反转后前节点...
publicclassSolution{publicListNodeReverseList(ListNode head){if(head==null)returnnull;//head为当前节点,如果当前节点为空的话,那就什么也不做,直接返回null;ListNode pre=null;ListNode nextnode=null;while(head!=null){nextnode=head.next;head.next=pre;pre=head;head=nextnode;}returnpre;}} Reverse Lin...
return p1 Reverse Linked List II Reverse a linked list from position m to n. Do it in-place and in one-pass. For example: Given 1->2->3->4->5->NULL, m = 2 and n = 4, return1->4->3->2->5->NULL. Note: Given m, n satisfy the following condition: 1 ≤ m ≤ n ≤ ...
A linked list can be reversed either iteratively or recursively. Could you implement both? 既然问了能否iteratively or recursively, 那就both把. iterative 解法: 总结就是得到下一个节点,更改当前节点指向,将指针往下移动,直到过完整个linkedlist.
def reverseList(self, head): """ :type head: ListNode :rtype: ListNode """ dummy = ListNode(None) while head: # 终止条件是head=Null nextnode = head.next # nextnode是head后面的节点 head.next = dummy # dummy.next是Null,所以这样head.next就成为了Null ...
反转是一种常见的编程操作,我们可以在许多场景中使用它。通过掌握这些基本的反转技巧,我们可以更好地处理Java编程中的问题。 参考文献: [Java StringBuilder reverse()]( [Reverse a number in Java]( [Reverse an Array in Java]( [Reverse a Linked List in Java](...
简介:Reverse a singly linked list.解题思路对于非递归实现,思路是依次将从第二个结点到最后一个结点的后继设为头结点,然后将该节点设为头结点(需记住将原头结点的后继设为空)。 对于递归实现,首先反转从第二个结点到最后一个结点的链表,然后再将头结点放到已反转链表的最后,函数返回新链表的头结点。非递归实...
The Java Program to reverse a Linked List iteratively and printing its elements is given below: package com.journaldev.linkedlist.reverse; import com.journaldev.linkedlist.reverse.MyLinkedList.Node; public class ReverseLinkedList { public static void main(String[] args) { ...
206 Reverse Linked List 反转链表 2018-04-08 18:07 −反转一个单链表。进阶:链表可以迭代或递归地反转。你能否两个都实现一遍?详见:https://leetcode.com/problems/reverse-linked-list/description/ Java实现: 迭代实现: /** * Definition for singly-linked... ...