此解法与第四种解法思路类似,只不过是将栈换成了数组,然后新建node节点,以数组最后一位元素作为节点值,然后开始循环处理每个新的节点。 publicListNodereverseList5(ListNode head){if(head ==null|| head.next ==null) {returnhead; } ArrayList<Integer> list =newArrayList<Integer>();while(head !=null) { ...
Output: 5->4->3->2->1->NULL /*** Definition for singly-linked list. * public class ListNode { * int val; * ListNode next; * ListNode(int x) { val = x; } * }*/classSolution {publicListNode reverseList(ListNode head) { ListNode curr=head; ListNode preNode=null;//反转后前节点...
return p1 Reverse Linked List II Reverse a linked list from position m to n. Do it in-place and in one-pass. For example: Given 1->2->3->4->5->NULL, m = 2 and n = 4, return1->4->3->2->5->NULL. Note: Given m, n satisfy the following condition: 1 ≤ m ≤ n ≤ ...
publicclassSolution{publicListNodeReverseList(ListNode head){if(head==null)returnnull;//head为当前节点,如果当前节点为空的话,那就什么也不做,直接返回null;ListNode pre=null;ListNode nextnode=null;while(head!=null){nextnode=head.next;head.next=pre;pre=head;head=nextnode;}returnpre;}} Reverse Lin...
A linked list can be reversed either iteratively or recursively. Could you implement both? 既然问了能否iteratively or recursively, 那就both把. iterative 解法: 总结就是得到下一个节点,更改当前节点指向,将指针往下移动,直到过完整个linkedlist.
def reverseList(self, head): """ :type head: ListNode :rtype: ListNode """ dummy = ListNode(None) while head: # 终止条件是head=Null nextnode = head.next # nextnode是head后面的节点 head.next = dummy # dummy.next是Null,所以这样head.next就成为了Null ...
How to reverse a Singly Linked List in Java https://www.youtube.com/playlist?list=PL6Zs6LgrJj3tDXv8a_elC6eT_4R5gfX4d 讲得比国内的老师清楚
简介:Reverse a singly linked list.解题思路对于非递归实现,思路是依次将从第二个结点到最后一个结点的后继设为头结点,然后将该节点设为头结点(需记住将原头结点的后继设为空)。 对于递归实现,首先反转从第二个结点到最后一个结点的链表,然后再将头结点放到已反转链表的最后,函数返回新链表的头结点。非递归实...
1/**2* Definition for singly-linked list.3* public class ListNode {4* int val;5* ListNode next;6* ListNode(int x) {7* val = x;8* next = null;9* }10* }11*/12publicclassSolution {13publicListNode reverseBetween(ListNode head,intm,intn) {14//Start typing your Java solution below...
25. Reverse Nodes in k-Group Given a linked list, reverse the nodes of a linked list k at a time and return its modified list. k is a positive integer and is less than or equal to the length of the linked list. If the number of nodes is not a multiple of k then left-out node...