方法一:(C++) 1classSolution {2public:3ListNode* reverseBetween(ListNode* head,intm,intn) {4ListNode* dummy=newListNode(-1),* pre=dummy;5pre->next=head;6intindex=0;7while(pre){8if(index==m-1)9break;10index++;11pre=pre->next;12}13ListNode* cur=pre->next;14for(intindex=m;index...
1/**2* Definition for singly-linked list.3* public class ListNode {4* int val;5* ListNode next;6* ListNode(int x) { val = x; }7* }8*/9publicclassSolution {10publicListNode reverseBetween(ListNode head,intm,intn) {11intcount = 1;12ListNode helper =newListNode(-1);13helper.next...
publicclassSolution{publicListNodereverseBetween(ListNode head,int m,int n){if(m==n||head==null||head.next==null){returnhead;}ListNode pre=newListNode(0);pre.next=head;ListNode Mpre=pre;ListNode NodeM=head;ListNode NodeN=head;int mNum=1;int nNum=1;while(mNum<m&&NodeM!=null){Mpre=...
Reverse a linked list from positionmton. Do it in-place and in one-pass. For example: Given1->2->3->4->5->NULL,m= 2 andn= 4, return1->4->3->2->5->NULL. 思路: 好困啊,脑子晕晕的。 转了半天AC了。但写的很罗嗦,要学习大神的写法。 注意翻转的写法。 用伪头部 大神14行简洁代...
Reverse a linked list from positionmton. Do it in one-pass. Note:1 ≤m≤n≤ length of list. Example: Input: 1->2->3->4->5->NULL, m = 2, n = 4 Output: 1->4->3->2->5->NULL 1. 2. 题解: classSolution{ public: ...
专业考题类型管理运行工作负责人一般作业考题内容选项A选项B选项C选项D选项E选项F正确答案 变电单选GYSZ本规程... 小白兔去钓鱼阅读 9,007评论 0赞 13 LeetCode 92. Reverse Linked List II 11-9 LeetCode 92. Reverse Linked List II Reverse Linked L... _kkk阅读 248评论 0赞 1 Leetcode 92. Reverse...
Leetcode260反转链表(java/c++/python) JAVA: class Solution { public ListNode reverseList(ListNode head) { if( head == null || head.next == null) return head; ListNode newHead = reverseList(head.next); head.next.next = head; head.next = null; return newHead; } } C++: class Solution...
LeetCode 206. 反转链表(Reverse Linked List) 示例: 输入:1->2->3->4->5->NULL输出:5->4->3->2->1->NULL 切题 一、Clarification 只需注意为空链表的情况 二、Possible Solution 1、迭代 2、递归 可利用哨兵简化实现难度 Python3 实现
C Plus Plus /** * Definitionforsingly-linked list. * struct ListNode { *intval; * ListNode *next; * ListNode(intx) : val(x),next(NULL) {} * }; */classSolution{ public: ListNode* reverseBetween(ListNode* head,intm,intn) {
Can you solve this real interview question? Reverse Linked List - Given the head of a singly linked list, reverse the list, and return the reversed list. Example 1: [https://assets.leetcode.com/uploads/2021/02/19/rev1ex1.jpg] Input: head = [1,2,3,