我们接下来要做的是,先把Mpre的next域指向NodeM节点的后一个节点; 再把NodeM所在节点移动到NodeN所在节点之后,使得NodeN的next域指向NodeM所在节点,NodeM所在节点next域指向NodeN的next域所指节点; 然后让NodeM指向Mpre的next域指向的节点; 演示图2 然后再重复上面的步骤; 这是NodeM和NodeN相遇,反转完成。 代码...
Reverse a linked list from position m to n. Do it in-place and in one-pass. For example: Given1->2->3->4->5->NULL, m = 2 and n = 4,return1->4->3->2->5->NULL. Note: Given m, n satisfy the following condition:1 ≤ m ≤ n ≤ length of list. Analysis: 这道题还是...
1 #include <iostream> 2 #include <malloc.h> 3 using namespace std; 4 5 struct ListNode { 6 int val; 7 ListNode *next; 8 ListNode(int x) : val(x), next(NULL) {} 9 }; 10 /*在链表的末端插入新的节点,建立链表*/ 11 ListNode *CreateList(int n) 12 { 13 ListNode *head; 14 L...
# Definition for singly-linked list. # class ListNode: # def __init__(self, val=0, next=None): # self.val = val # self.next = next class Solution: def reverseBetween(self, head: Optional[ListNode], left: int, right: int) -> Optional[ListNode]: i = 0 p = head p_l = None...
publicListNodereverseBetween(ListNodehead,intm,intn){if(m==n){returnhead;}ListNodedummy=newListNode(0);dummy.next=head;intcount=0;ListNodeleft1=null;ListNodeleft2=null;ListNodepre=dummy;while(head!=null){count++;//到达 m,保存 l1 和 l2if(count==m){left1=pre;left2=head;}// m 和 n ...
Reverse a linked list from positionmton. Do it in-place and in one-pass. For example: Given1->2->3->4->5->NULL,m= 2 andn= 4, return1->4->3->2->5->NULL. 思路: 好困啊,脑子晕晕的。 转了半天AC了。但写的很罗嗦,要学习大神的写法。 注意翻转的写法。
Reverse a linked list from position m to n. Do it in one-pass. Example: Input: 1->2->3->4->5->NULL, m = 2, n = 4 Output: 1->4->3->2->5->NULL Note: 1≤ m ≤ n ≤ length of list. 解释下题目: 在一次循环中把链表指定位置倒序 ...
Reverse a linked list from positionmton. Do it in one-pass. Note:1 ≤m≤n≤ length of list. Example: Input: 1->2->3->4->5->NULL, m = 2, n = 4 Output: 1->4->3->2->5->NULL 1. 2. 题解: classSolution{ public: ...
reverse-linked-list-ii DaiMorph关注IP属地: 加州 2019.04.19 19:40:47字数165阅读287 对于reverse部分有点迷糊。网上看到的解释,也许更能帮助理解.https://yq.aliyun.com/articles/3867 不妨拿出四本书,摞成一摞(自上而下为 A B C D),要让这四本书的位置完全颠倒过来(即自上而下为 D C B A): ...
92. Reverse Linked List II Reverse a linked list from position m to n. Do it in-place and in one-pass. For example: Given 1->2->3->4->5->NULL, m = 2 and n = 4, return 1->4->3->2->5->NULL. Note: Giv...