## 解法二:除法解法 class Solution: def reverse(self, x:int) -> int: sign = 1 if x>=0 else -1 ans =0 x=abs(x) while x!=0: ans = ans*10 + x%10 ## 把最右边一位数字,逐一翻到最前面 x = x //10 ## 丢掉最后一位 return ans*sign if ans<2**31-1 and ans>=-2*31 ...
classSolution {public:intreverse(intx) {if(x<=9&& x>=-9)returnx;intMAX = INT_MAX/10;intMIN = INT_MIN/10;intresult =0;while(x !=0){if( result>MAX || result<MIN||(x >0&& INT_MAX-x%10<result*10)|| (x<0&& INT_MIN-x%10>result*10) )return0; result= result*10+ x%...
LeetCode 7 :Reverse Integer --- 反转int整数 原题链接: https://leetcode.com/problems/reverse-integer/ 一:原题内容 Reverse digits of an integer. Example1:x = 123, return 321 Example2:x = -123, return -321 二:分析理解 我们需要考虑反转后的数可能会溢出int给出的大小,而且...
Assume we are dealing with an environment which could only store integers within the 32-bit signed integer range: [−231, 231 − 1]. For the purpose of this problem, assume that your function returns 0 when the reversed integer overflows. 注意:假设我们的环境只能存储得下 32 位的有符号...
【Leetcode】Reverse Integer https://leetcode.com/problems/reverse-integer/题目: Reverse digits of an integer. Example1: x = 123, return 321 Example2: 思路: 注意正负情况 算法: 1. public int reverse(int x) { 2. char c[] = String.valueOf(Math.abs(x)).toCharArray();...
输入:-1234 输出:-4321 3. 输入:120 输出:21 注意:反转数字后的大小是否在int范围之内 Java解法一:我分成两种情况讨论,正负数,利用StringBuilder().reverse().toString()进行反转,再分别与Integer.MIN_VALUE/Integer.MAX_VALUE比较,符合返回结果值,不符合返回0 ...
Given a32-bitsigned integer, reverse digits of an integer. Example 1: Input: 123 Output: 321 Example 2: Input: -123 Output: -321 Example 3: Input: 120 Output: 21 Note: Assume we are dealing with an environment which could only store integers within the32-bit signedinteger range: [−...
陆陆续续在LeetCode上刷了一些题,一直没有记录过,准备集中整理记录一下 java:classSolution{publicint reverse(int x){long num=0;while(x!=0){num=num*10+x%10;x=x/10;}if(num>=Integer.MAX_VALUE||num<=Integer.MIN_VALUE){return0;}return(int)num;}}python:classSolution:defreverse(self,x):...
其他Java相关优化操作: 数组最大长度为tokens.length / 2 + 1 switch代替if-else,效率优化 Integer.parseInt代替Integer.valueOf,减少自动拆箱装箱操作 附两种方法:纯数组模拟栈实现(推荐):栈实现: 栈 Java 数组 106 16.8K 32Adoring ・ 2025.02.18 数字入栈、符号计算 Code C++ 栈 1 177 0...
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