Example: Input: 1->2->3->4->5->NULL Output: 5->4->3->2->1->NULL /*** Definition for singly-linked list. * public class ListNode { * int val; * ListNode next; * ListNode(int x) { val = x; } * }*/classSolution {publicListNode reverseList(ListNode head) { ListNode curr=...
解法二(Java) /*** Definition for singly-linked list. * public class ListNode { * int val; * ListNode next; * ListNode(int x) { val = x; } * }*/classSolution {publicListNode reverseList(ListNode head) {if(head ==null|| head.next ==null)returnhead;//处理最小输入的情况,即空链表...
Reverse Linked List II Reverse a linked list from position m to n. Do it in-place and in one-pass. For example: Given 1->2->3->4->5->NULL, m = 2 and n = 4, return1->4->3->2->5->NULL. Note: Given m, n satisfy the following condition: 1 ≤ m ≤ n ≤ length of ...
node=dummyfor__inrange(m-1):#1node=node.next prev=node.next # prev.val=2curr=prev.next # curr.val=3for__inrange(n-m):# 翻转2次,和直接翻转全部链表不同的是,这里条件就是翻转次数,不通过head指向null判断,毕竟也不指向null,后面还有数字 nextnode=curr.next curr.next=prev prev=curr curr=n...
def reverseList(self, head): """ :type head: ListNode :rtype: ListNode """ dummy = ListNode(None) while head: # 终止条件是head=Null nextnode = head.next # nextnode是head后面的节点 head.next = dummy # dummy.next是Null,所以这样head.next就成为了Null ...
How to reverse a Singly Linked List in Java https://www.youtube.com/playlist?list=PL6Zs6LgrJj3tDXv8a_elC6eT_4R5gfX4d 讲得比国内的老师清楚
Reverse a singly linked list. click to show more hints. Hint: A linked list can be reversed either iteratively or recursively. Could you implement both? 既然问了能否iteratively or recursively, 那就both把. iterative 解法: 总结就是得到下一个节点,更改当前节点指向,将指针往下移动,直到过完整个linked...
1/**2* Definition for singly-linked list.3* public class ListNode {4* int val;5* ListNode next;6* ListNode(int x) {7* val = x;8* next = null;9* }10* }11*/12publicclassSolution {13publicListNode reverseBetween(ListNode head,intm,intn) {14//Start typing your Java solution below...
25. Reverse Nodes in k-Group Given a linked list, reverse the nodes of a linked list k at a time and return its modified list. k is a positive integer and is less than or equal to the length of the linked list. If the number of nodes is not a multiple of k then left-out node...
做II之前应该先来做1的,这个倒是很简单,基本上不用考虑什么,简单的链表反转而已: 1 /** 2 * Definition for singly-linked list. 3 * struct ListNode { 4 * ... eversliver 0 276 反转链表算法Java实现 2018-12-11 13:25 − 之前遇到反转链表的算法,比较晦涩难解,但其实挺简单的。 目标:将一...