publicStringreverseWords(Strings){if(s==null)returnnull;char[]a=s.toCharArray();intn=a.length;// step 1. reverse the whole stringreverse(a,0,n-1);// step 2. reverse each wordreverseWords(a,n);// step 3. clean up spacesreturncleanSpaces(a,n);}voidreverseWords(char[]a,intn){int...
self.reverseEachWord(l) #3.翻转每个单词 # ['t','o','d','a','y',' ','r','a','i','n','i','n','g',' ','i','s',' ','i','t'] return''.join(l) #1.去除头中尾空格 def rmExtraSpaces(self, s): n=len(s) left=0 right=n-1 # rm开头空格 whileleft<=rightand...
public void reverseEachWordInString(String str1) { // Split the input string into individual words. String[] each_words = str1.split(" "); String revString = ""; // Iterate through each word in the array. for (int i = 0; i < each_words.length; i++) { String word = each_w...
Given a string, you need to reverse the order of characters in each word within a sentence while still preserving whitespace and initial word order. 示例1: 代码语言:javascript 代码运行次数: 输入:"Let's take LeetCode contest"输出:"s'teL ekat edoCteeL tsetnoc" 注意:在字符串中,每个单词由单...
Given a string, you need to reverse the order of characters in each word within a sentence while still preserving whitespace and initial word order. Example 1: Input: "Let's take LeetCode contest" Output: "s'teL ekat edoCteeL tsetnoc" ...
self.reverseEachWord(l) # 3.翻转每个单词 # ['t', 'o', 'd', 'a', 'y', ' ', 'r', 'a', 'i', 'n', 'i', 'n', 'g', ' ', 'i', 's', ' ', 'i', 't'] return ''.join(l) # 1.去除头中尾空格 def rmExtraSpaces(self, s): ...
151. Reverse Words in a String Given an input string, reverse the string word by word. Example 1: Input: "the sky is blue" **Output: **"blue is sky the" Example 2: Input: " hello world! " **Output: **"world! hello" Explanation: Your reversed string should not contain leading...
Explanation: You need to reduce multiple spaces between two words to a single space in the reversed string. Note: A word is defined as a sequence of non-space characters. Input string may contain leading or trailing spaces. However, your reversed string should not contain leading or trailing ...
In the string, each word is separated by single space and there will not be any extra space in the string. 思路 该题考察对字符串中的单词翻转,只需要找空格即可。用b记录单词起始位置,找到空格即一个单词结束,对从b到当前位置的字符串进行翻转。翻转直接使用reverse函数即可。 代码 class Solution { pu...
StringStrRev=sb.reverse().toString();// Split the reversed string into words.String[]words=StrRev.split(" ");// Create a StringBuilder to store the reversed words.StringBuilderreverse=newStringBuilder();// Iterate through each word, reverse it, and append it to the result string.for(String...