解法1:字符串反转 解法2:数学运算(求余)转换 解法3:递归解法 这个题其实是 LeetCode 9 的基础题。可见,LeetCode 的题目编排就是乱来。 不过呢,相对 LeetCode 9,此题存在一些小的细节必须考虑周全。 题目要求看上去很简单,就是把一个整数从右到左翻过来。比如5,翻过来还是5;123,翻过来就是 321;-124,反过...
Reverse digits of an integer. Example1: x = 123, return 321 Example2: x = -123, return -321 题目提示: Have you thought about this? Here are some good questions to ask before coding. Bonus points for you if you have already thought through this! If the integer’s last digit is 0,...
通过字符串转换,由于stoi()函数会作int范围检查,利用异常处理机制。 思路3:字符串分片(python) python中int都是长整型,可以通过直接比较32位整数大小来判断是否溢出。通过字符串分片来完成反转。 Tips C++知识 integer范围:−231∼231−1−231∼231−1 short为半个机器字长,int为一个机器字长,long类型为...
if (rev < Integer.MIN_VALUE/10 || (rev == Integer.MIN_VALUE / 10 && pop < -8)) return 0; rev = rev * 10 + pop; } return rev; } } 1. 2. 3. 4. 5. 6. 7. 8. 9. 10. 11. 12. 13. Python python没有溢出问题,处理这题投机取巧 class Solution(object): def reverse(sel...
Given a 32-bit signed integer, reverse digits of an integer. Example 1: Input: 123 Output: 321 Example 2: Input: -123 Output: -321 Example 3: Input: 120 Output: 21 Solution: https://leetcode.com/problems/reverse-integer/discuss/229800/Python3-Faster-than-100 ...
int(x), to convert x into an integer value long(x), to convert x into a long integer value float(x), to convert x into a floating-point number complex(x), to convert x into a complex number where the imaginary part stays 0 and x becomes the real part complex(x,y), to convert...
The input is assumed to be a 32-bit signed integer. Your function shouldreturn 0 when the reversed integer overflows. 解题思路: python里面int最大数值0x7FFFFFFF,在考虑溢出的时候需要和这个值进行比较。 取模运算可以得到数字的最后一位,/运算会得到移走最后一个数字之外的数字,以此循环 ...
[966星][7m] [PHP] jenssegers/optimus id transformation With this library, you can transform your internal id's to obfuscated integers based on Knuth's integer has和 [906星][7m] [C++] dfhack/dfhack Memory hacking library for Dwarf Fortress and a set of tools that use it [895星][12m] ...
java:classSolution{publicint reverse(int x){long num=0;while(x!=0){num=num*10+x%10;x=x/10;}if(num>=Integer.MAX_VALUE||num<=Integer.MIN_VALUE){return0;}return(int)num;}}python:classSolution:defreverse(self,x):""":typex:int:rtype:int"""ifx<0:s=str(abs(x))res=0-int(s[...
from sage.stats.distributions.discrete_gaussian_integer import DiscreteGaussianDistributionIntegerSampler import os, random, sys, string from minipwn import * from itertools import * from hashlib import sha256 from Crypto.Util.number import bytes_to_long,long_to_bytes ...