The source code to reverse a string using recursion is given below. The given program is compiled and executed using GCC compile on UBUNTU 18.04 OS successfully. // C program to reverse a string using recursion#
Program to reverse a string using pointers in C language with compelete explanation.
-- Create a function named reverse_string that takes a text input and returns a text value CREATE FUNCTION reverse_string(str TEXT) RETURNS TEXT AS $$ BEGIN -- Return the reversed version of the input string using the REVERSE function RETURN REVERSE(str); END; -- Specify the language ...
In the above program, we imported a package Swift to use the print() function using the below statement,import Swift; Here, we created a string str initialized with "Hello India". Then we reversed the created string using reversed() function and assigned the result into result and printed ...
Inside the loop, the reversed number is computed using: reverse = reverse * 10 + remainder; Let us see how the while loop works when n = 2345. nn != 0remainderreverse 2345 true 5 0 * 10 + 5 = 5 234 true 4 5 * 10 + 4 = 54 23 true 3 54 * 10 + 3 = 543 2 true 2 54...
Approach 2 – Using spread operator const ReverseString = str => [...str].reverse().join(''); ReverseString("codedamn") //Output- nmadedocCode language: JavaScript (javascript) Here the spread operator is used to convert string to an array of characters(codedamn={c,o,d,e,d,a,m,...
Write a C# Sharp program to reverse a given string in uppercase. Sample Solution:- C# Sharp Code: usingSystem;usingSystem.Linq;namespaceexercises{classProgram{staticvoidMain(string[]args){// Display original string and its uppercase transformationConsole.WriteLine("Original string: php");Console....
#include <bits/stdc++.h> using namespace std; bool isVowel(char ch) { return ch == 'a' || ch == 'e' || ch == 'i' || ch == 'o' || ch == 'u' || ch == 'A' || ch == 'E' || ch == 'I' || ch == 'O' || ch == 'U'; } string reverseVowel(string ...
Reverse a number using functional programming. Args: number: The number to reverse Returns: The reversed number """ # Handle negative numbers is_negative = number < 0 number = abs(number) # Convert to string for digit extraction digits = [int(d) for d in str(number)] ...
importarrayasarr a=arr.array('i',[10,5,15,4,6,20,9])b=arr.array('i')foriinrange(len(a)-1,-1,-1):b.append(a[i])print(a)print(b) It will produce the followingoutput− array('i', [10, 5, 15, 4, 6, 20, 9]) array('i', [9, 20, 6, 4, 15, 5, 10]) ...