Approach 2 – Using spread operator const ReverseString = str => [...str].reverse().join(''); ReverseString("codedamn") //Output- nmadedocCode language: JavaScript (javascript) Here the spread operator is used to convert string to an array of characters(codedamn={c,o,d,e,d,a,m,...
Below is a program to reverse a string using pointer:#include <stdio.h> int main() { printf("\n\n\t\tStudytonight - Best place to learn\n\n\n"); char str[100]; char rev[100]; char *sptr = str; // sptr stores the base address of the str char *rptr = rev; // rptr ...
// C program to reverse a string using recursion#include <string.h>#include <stdio.h>voidStrRev(charstr[],inti,intlen) {chart;intj; j=len-i; t=str[i]; str[i]=str[j]; str[j]=t;if(i==len/2)return; StrRev(str, i+1, len); }intmain() {charstr[20];intlen=0; printf("...
{usingnamespacestd;//1KW 字符串反序函数测试,分别测试同样算法,string 和 C风格字符串的区别stringstr ="0123456789ABCDEFGHIJKLMNOPQRSTUVWXYZ";for(inti =0; i !=10000001; i++)//STL_Reverse(str);//0.313秒//good_Reverse(str);//0.875秒//Reverse(str);//1.063秒bad_Reverse(str);//7.016秒cout...
saving you a byte of memory... For another 4 bytes, find the end of the string yourself using a single pointer instead of using strlen which needs a 4-byte integer. Now you're down to two char*'s ... I would be surprised if there is a solution that uses less than that ... se...
Here’s a solution in C: #include<string.h>#include<assert.h>#include<stdlib.h>voidreverse(char*s){intleft=0;intlen=0;for(;s[len]!='\0';len++);while(len>1){charleft_c=s[left];s[left]=s[left+len-1];s[left+len-1]=left_c;left++;len-=2;}}voidtest(char*input,char*out...
Then in the project, we will develop a recursion function which we will call later on in the code for reversing the strings. Declare a function with the return type “void” and name it “reverse.” The parameters of this function will be char type pointer string as “char*string.” In...
class Solution: """ @param: s: A string @return: A string """ def reverseWords(self, s): #writeyour code here pointer =0ls= []fori inrange(len(s)): # beginning ofawordifs[i] ==' ':ifi ==len(s) -1:breakifs[i +1] !=' ': pointer = i +1# the end ofawordifs[i...
A simple function that prints out a word that starts from the current character pointer. We loop and print till we get a end-of-string ('\0') or a blank: #include<iostream>voidprint_word(constchar* x){while(*x !=' '&& *x !='\0'){ ...
Here is a simple example to reverse characters in String by using two pointer technique. This is anin-place algorithmbecause it doesn't allocate any extra array, it just uses the two integer variables to hold positions from start and end. ...