// Define a function named 'reverse_string' that takes a string as input and returns its reversefnreverse_string(input:&str)->String{// Create a new String to store the reversed stringletmutreversed_string=String::new();// Iterate over the characters of the input string in reverse orderf...
Lintcode53 Reverse Words in a String solution 题解 【题目描述】 Given an input string, reverse the string word by word. 给定一个字符串,逐个翻转字符串中的每个单词。 【题目链接】 http://www.lintcode.com/en/problem/reverse-words-in-a-string/ 【题目解析】 这道题让我们翻转字符串中的单词,题...
Could the input string contain leading or trailing spaces? Yes. However, your reversed string should not contain leading or trailing spaces. How about multiple spaces between two words? Reduce them to a single space in the reversed string. SOLUTION 1: 1. 先处理原字符串: 使用strim把前后的空格...
Reverse a String Problem You need to reverse the order of letters in a string. Solution Convert the string to an array of characters and use theArray.Reversemethod, or use the legacyStrReverseVisual Basic 6 function. Discussion The functionality for reversing a string isn’t built into the...
考虑几个特殊的情况 1.若字符窜s=" " 2.字符窜s=“a b d e” 3.字符窜s=“ a”然后在s后面+上一个‘ ’,每次遇到s[i]为空格,s[i-1]不为空格的时候为一个单词 class Solution { public: void reverseWords(string &s)...
1publicclassSolution {2publicString reverseVowels(String s) {3if(null== s)returns;4char[] tmp =s.toCharArray();5Stack<Character> stack =newStack<Character>();6for(inti = 0; i<tmp.length; i++){7if(isVowels(tmp[i])){8stack.push(tmp[i]);9}10}11for(inti = 0; i<tmp.length;...
A lot simler in .NET it is: static string ReverseWords(string str) { string[] words = str.Split(' '); Array.Reverse(words); return string.Join(" ", words); } Abhinaba Basu [MSFT] August 2, 2007 Nope the .NET solution won't work as that is not constant space. E.g. your ...
3.调用C++ STL的方式,<algorithm>中有一个reverse函数,用于翻转各种可以使用双向迭代器的东西。代码如下: 1classSolution {2public:3stringreverseString(strings) {4reverse(&s[0],&s[s.length()]);5returns;6}7}; reverse函数介绍:http://zh.cppreference.com/w/cpp/algorithm/reverse ...
Output:["h","a","n","n","a","H"] 代码实现(个人版): 1classSolution:2defreverseString(self, s) ->None:3"""4Do not return anything, modify s in-place instead.5"""6s[:] = s[::-1]78if__name__=='__main__':9x = ['h','e','l','l','o']10y =Solution().reverse...
Output:["h","a","n","n","a","H"] 这道题没什么难度,直接从两头往中间走,同时交换两边的字符即可,参见代码如下: 解法一: classSolution {public:voidreverseString(vector<char>&s) {intleft =0, right = (int)s.size() -1;while(left <right) {chart =s[left]; ...