#include <array> using namespace std; class Solution { public: int reversePairs(vector<int>& a) { if (a.size() <= 0) return 0; vector<long long> all(a.begin(), a.end()); return mergeSort(all, 0, all.size() - 1); } long long mergeSort(vector<long long>& a, int begin...
191 Number of 1 Bits Bit Manipulation Python ⭐ Data Stream 相關題型 ⭐ [Lint] 642 Moving Average from Data Stream Data Stream Queue Python ⭐ Design 相關題型 ⭐ 155 Min Stack Design Python [Lint] 659 Encode and Decode Strings Design Python 232 Implement Queue using Stacks Design...
pre->order part->inorder part->left_out Now it's the code #include <iostream>#include<vector>#include<iostream>#include<string>#include<stdio.h>#include<string.h>#include<iomanip>#include<vector>#include<list>#include<queue>#include<algorithm>#include<stack>#include<map>usingnamespacestd;str...
Reverse Linked List https://leetcode.com/problems/reverse-linked-list/ Constraints: The number of nodes in the list is the range [0, 5000]. -5000 <= Node.val <= 5000 1. 2. Idea Using a dummy head could make things easier. For each node in the list: Set node as dummy...
My Solutions to Leetcode problems. All solutions support C++ language, some support Java and Python. Multiple solutions will be given by most problems. Enjoy:) 我的Leetcode解答。所有的问题都支持C++语言,一部分问题支持Java语言。近乎所有问题都会提供多个算
WebGL: Count the number of rendered vertices Using the WebGL API, is there a way to count the number of vertices rendered within a given canvas? I've seen some tools that attempt to accomplish this task but some are giving strange results (e.g. ... ...
Now it's the code #include <iostream>#include<vector>#include<iostream>#include<string>#include<stdio.h>#include<string.h>#include<iomanip>#include<vector>#include<list>#include<queue>#include<algorithm>#include<stack>#include<map>usingnamespacestd;structListNode {intval; ...
186 now we are given string in char array. and we need to reverse the order of those words: a little trick, reverse everything, and then reverse every words. 557: “Let’s take LeetCode contest”–> “s’teL ekat edoCteeL tsetnoc”, it is very simple. ...