Reverse a linked list. 翻转一个链表 【题目链接】 http://www.lintcode.com/en/problem/reverse-linked-list/ 【题目解析】 这题要求我们翻转[m, n]区间之间的链表。对于链表翻转来说,几乎都是通用的做法,譬如p1 -> p2 -> p3 -> p4,如果我们要翻转p2和p3,其实就是将p3挂载到p1的后面,所以我们需要知...
1 <= m <= n <=length of list.A: 要小心循环次数!ListNode *reverseBetween(ListNode *head, int m, int n) { // Start typing your C/C++ solution below // DO NOT write int main() function if(m==n||!head) return head; ListNode *tail = NULL,*prev = NULL,*cur,*temp,*next=...
Reverse a linked list from positionmton. Do it in-place and in one-pass. For example: Given1->2->3->4->5->NULL,m= 2 andn= 4, return1->4->3->2->5->NULL. Note: Givenm,nsatisfy the following condition: 1 ?m?n? length of list. classSolution {public:voidreverse(ListNode *...
code例如以下: classSolution{public:ListNode*reverseBetween(ListNode*head,intm,intn){if(head==NULL||m<0||n<0)returnhead;if(head->next==NULL||m==n)returnhead;ListNode*head2=NULL,*pre,*cur,*temp=head;for(inti=0;i<n+1;i++){if(i==m-2)head2=temp;elseif(i==m-1)cur=temp;else...
Submitted by Radib Kar, on December 02, 2018 Problem statement: Given a linked list reverse it without using any additional space (In O(1) space complexity).SolutionReversing a single linked list is about reversing the linking direction. We can solve the above problem by following steps:1...
Can you solve this real interview question? Reverse Linked List - Given the head of a singly linked list, reverse the list, and return the reversed list. Example 1: [https://assets.leetcode.com/uploads/2021/02/19/rev1ex1.jpg] Input: head = [1,2,3,
ListNode c(3); ListNode d(4); ListNode e(5); a.next = &b; b.next = &c; c.next = &d; d.next = &e; Solution solve; ListNode *head = solve.reverseBetween(&a, 2, 4); while (head) { printf("%d ",
Write a C program to reverse alternate k nodes of a given singly linked list. Sample Solution:C Code:#include<stdio.h> #include <stdlib.h> // Definition for singly-linked list struct Node { int data; struct Node* next; }; // Function to create a new node in the linked list struct...
Reverse a linked list from positionmton. Do it in one-pass. Note: 1 ≤m≤n≤ length of list. Example: Input: 1->2->3->4->5->NULL, m = 2, n = 4Output:1->4->3->2->5->NULL 根据经验,先建立一个虚结点dummy node,连上原链表的头结点,这样的话就算头结点变动了,我们还可以通过...
LeetCode: Reverse Linked List Reverse a linked list from positionmton. Do it in-place and in one-pass. For example: Given1->2->3->4->5->NULL,m= 2 andn= 4, return1->4->3->2->5->NULL. Note: Givenm,nsatisfy the following condition: ...