@return: You should return the head of the reversed linked list. Reverse it in-place. """defreverse(self,head):# case1: empty listifheadisNone:returnhead# case2: only one element listifhead.nextisNone:returnhead# case3: reverse from the rest after headnewHead=self.reverse(head.next)#...
Btw, if you get this question asked in the real interview, you would be most likely asked to reverse the linked list using recursion now. So, wait for another article to see that solution or check out theCracking the Coding Interviewbook, which contains a solution to this problem along wit...
click to show more hints. Hint: A linked list can be reversed either iteratively or recursively. Could you implement both? Subscribeto see which companies asked this question 1/**2* Definition for singly-linked list.3* public class ListNode {4* int val;5* ListNode next;6* ListNode(int x...
Can you solve this real interview question? Reverse Linked List - Given the head of a singly linked list, reverse the list, and return the reversed list. Example 1: [https://assets.leetcode.com/uploads/2021/02/19/rev1ex1.jpg] Input: head = [1,2,3,
Data Structures - how to reverse a linked list without usinf any pointer of c? . 2 Answers are available for this question.
Question Reverse a linked list from position m to n. Do it in-place and in one-pass. For example: Given 1->2->3->4->5->NULL, m = 2 and n = 4, return 1->4->3->2->5->NULL. Note: ...
def reverse_linked_list(head): prev = None curr = head while curr: next_node = curr.next curr.next = prev prev = curr curr = next_node return prev # 测试 node1 = ListNode(1) node2 = ListNode(2) node3 = ListNode(3) node1.next = node2 node2.next = node3 reversed_head = re...
Can you solve this real interview question? Reverse Nodes in k-Group - Given the head of a linked list, reverse the nodes of the list k at a time, and return the modified list. k is a positive integer and is less than or equal to the length of the linke
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