where pA and pB are the hydrostatic stresses at points A and B, respectively. Finally, the unknown parameter Cn is given by [32]Cn=(pA−pB)[A+B(ε¯AB)n]2kABnB(ε¯AB)n In Oxley's theory, the angle θ made by the resultant force FR with AB is expressed as [33]tanθ=1...
I've got a question concerning the resultant force due to hydrostatic pressure. I understand how to calculate an object with uniform dimensions as depth (and pressure) increase. But I got thrown a serious curve ball on a Statics test. The situation was such: A downward facing isosceles... ...