The height and width of the given matrix is in range [1, 100]. The given r and c are all positive. 题意将一个矩阵的行列改变,但不改变里面的数值。 我的做法是直接遍历原矩阵赋给新矩阵,C++实现如下 vector<vector<int>> matrixReshape(vector<vector<int>>& nums,intr,intc) {introw=nums.size...
leetCode题解之Reshape the Matrix 1、题目描述 2、分析 使用了一个队列。 3、代码 1vector<vector<int>> matrixReshape(vector<vector<int>>& nums,intr,intc) {23if( nums.size() * nums[0].size() != r *c )4returnnums;5vector<vector<int>>ans;6queue<int>q;7for( size_t i =0; i < ...
You're given a matrix represented by a two-dimensional array, and two positive integers r and crepresenting the row number and column number of the wanted reshaped matrix, respectively. The reshaped matrix need to be filled with all the elements of the original matrix in the same row-traver...
The reshaped matrix need to be filled with all the elements of the original matrix in the same row-traversing order as they were. If the 'reshape' operation with given parameters is possible and legal, output the new reshaped matrix; Otherwise, output the original matrix. Example 1: Input:...
leetcode566. Reshape the Matrix https://leetcode.com/problems/reshape-the-matrix/description/ publicint[][] matrixReshape(int[][] nums,intr,intc) {intm = nums.length, n = nums[0].length;if(r * c != m *n)returnnums;int[][] reshaped =newint[r][c];for(inti =0; i < r *...
LeetCode #566. Reshape the Matrix 题目 566. Reshape the Matrix 解题方法 先判断能否reshape,如果可以再把原数组拆成一个一维数组,之后按照rc重新放置即可。 时间复杂度:O(rc) 空间复杂度:O(r*c) 代码 class Solution: def matrixReshape(self, nums: List[List[int]], r: int, c: int) -> List[...
题目地址:https://leetcode.com/problems/reshape-the-matrix/description/ 题目描述 In MATLAB, there is a very useful function called ‘reshape’, which can reshape a matrix into a new one with different size but keep its original data.
题目链接:Leetcode 54. Spiral Matrix 思考思路:就是矩阵的一个搜索遍历,用到思想就是要dx\dy 来控制方向,正如 (0,0,-1,1)这样的方向选择,就是选择不同方向,要思考的就是什么时候转变方向。 代码如下 参考链接 Leetcode 54. Spiral Matrix...
566. Reshape the Matrix 回到顶部 题意 给定一个矩阵和新的行数和列数。输出变形后的矩阵。 回到顶部 思路 利用给定的行数和列数构造一个二维数组,再将原矩阵中的数一个一个进行填充。 回到顶部 代码 Java 1: publicclassSolution{publicint[][] matrixReshape(int[][] nums,intr,intc) {if(r * c !
Java Solution: Runtime beats 38.21% 完成日期:05/10/2017 关键词:Array 关键点:自己来计数row and column, 并存入每一个int到新的2d array里面 1publicclassSolution2{3publicint[][] matrixReshape(int[][] nums,intr,intc)4{5//check if new array is possible.6if(nums.length * nums[0].length ...