解法一:暴力解法 ## 用 replace 函数classSolution:defremoveVowels(self,s:str)->str:foriins:ifiin"aeiou":s=s.replace(i,"")returns## 逐个子母来收集非元音defremoveVowels(s:str)->str:vowels="aeiou"result=""forcharins:ifcharnotinvowels:result+=charreturnresult 复杂度分析: 时间复杂度:O(n)...
1classSolution {2func removeVowels(_ S: String) ->String {3let arrS:[Character] =Array(S)4varret:String =String()5foriin0..<S.count6{7ifarrS[i] =="a"|| arrS[i] =="e"|| arrS[i] =="i"|| arrS[i] =="o"|| arrS[i] =="u"8{9continue10}11else12{13ret.append(a...
1119. Remove Vowels from a String - Easy Given a stringS, remove the vowels'a','e','i','o', and'u'from it, and return the new string. Example 1: Input:"leetcodeisacommunityforcoders" Output:"ltcdscmmntyfrcdrs" Example 2: Input:"aeiou" Output:"" Note: Sconsists of lowercase En...
全部题解 题解不存在 请查看其他题解 智能模式 1 行1,列 1 运行和提交代码需要登录 Case 1Case 2 s = "leetcodeisacommunityforcoders" 1 2 "leetcodeisacommunityforcoders" "aeiou" Source 该题目是 Plus 会员专享题 感谢使用力扣!您需要升级为 Plus 会员来解锁该题目升级Plus 会员标签...
# Definition for singly-linked list. # class ListNode: # def __init__(self, x): # self.val = x # self.next = None class Solution: def deleteDuplicates
Given a sorted arraynums, remove the duplicatesin-placesuch that duplicates appeared at mosttwiceand return the new length. Do not allocate extra space for another array, you must do this by modifying the input arrayin-placewith O(1) extra memory. ...