* };*/classSolution {public: ListNode* removeElements(ListNode* head,intval) {if(head && head->val==val) head=removeElements(head->next,val);if(head && head->next) head->next=removeElements(head->next,val);returnhead; } };
/** * Definition for singly-linked list. * struct ListNode { * int val; * struct ListNode *next; * };*/structListNode* removeElements(structListNode* head,intval) {if(head ==NULL)returnNULL;structListNode* tmp =head;structListNode* tmp2 =NULL;while(head->val ==val) { tmp2=head; h...
Can you solve this real interview question? Remove Linked List Elements - Given the head of a linked list and an integer val, remove all the nodes of the linked list that has Node.val == val, and return the new head. Example 1: [https://assets.leetc
Remove all elements from a linked list of integers that have valueval. Example: Input: 1->2->6->3->4->5->6, val = 6 Output: 1->2->3->4->5 1. 2. 题解: 增加个头结点指向需要删除结点的前面就好了 classSolution{ public: ListNode*removeElements(ListNode*head,intval) { ListNode*t...
Remove all elements from a linked list of integers that have value val. Example : AI检测代码解析 Input:1->2->6->3->4->5->6,val=6Output:1->2->3->4->5 1. 2. 题目大意 删除链表中所有指定值的结点。 解题思路 按照题意做即可。
Remove all elements from a linked list of integers that have value val. Example Given: 1 --> 2 --> 6 --> 3 --> 4 --> 5 --> 6, val = 6 Return: 1 --> 2 --> 3 --> 4 --> 5 一刷 题解:很简单,直接上代码吧。
https://leetcode.com/problems/remove-linked-list-elements 和常规的删除一个node的情况不同的是,它要求删除所有val为指定值的node。 这道题要注意一个点: head node 的值是指定值,和中间node的值为指定值,在操作上不一样。比较好的办法是,在head前创建一个dummy node,那么这两种情况的操作就一样,最后返回...
This fusion gene has all the promoter elements of Zfy2 but has the terminal exons 6-11 of Zfy1 that encompass all but the first 20 amino acids of the open reading frame. It is therefore expected to express, with the pattern of expression of Zfy2, a protein identical to ZFY1 aside ...
[LeetCode]--203. Remove Linked List Elements 简介:Remove all elements from a linked list of integers that have value val.Example Given: 1 –> 2 –> 6 –> 3 –> 4 –> 5 –> 6, val = 6 Return: 1 –> 2 –> 3 –> 4 –>...
func removeElements(head *ListNode, val int) *ListNode { if head == nil { return head } var p1 ListNode p1.Next = head p2 := &p1 for head != nil { if head.Val == val { p2.Next, head = head.Next, head.Next } else { p2, head = head, head.Next } } return p1.Next ...