del 也可以删除整个数据对象(列表、集合等) >>> str=[0,1,2,3,4,5,6]>>> del str>>> str#删除后,找不到对象Traceback (most recent call last):File"<pyshell#27>", line1,in<module>strNameError:name'str'isnotdefined 注意:del是删除引用(变量)而不是删除对象(数据),对象由自动垃圾回收机制...
Traceback (most recent call last): File "<pyshell#7>", line 1, in <module> list1.remove(6) ValueError: list.remove(x): x not in list 1. 2. 3. 4. 5. 6. 7. 8. 9. 10. 11. 12. 13. 当要删除list1中值为6的元素时,因为list1中不包含改元素,因此程序会显示异常,该异常的信息...
件产品我们的洗发水有1件产品我们要购买一件洗发水现在我们的洗发水还剩下0件,当前已经没有洗发水了 Traceback(mostrecentcalllast): File"/Users/llq/PycharmProjects/pythonlearn/python_list/list_remove.py",line11,in<module> shops.remove('洗发水') ValueError:list.remove(x):xnotinlist 进程已结束,...
list1.remove(list1) AI代码助手复制代码 输出: Traceback (most recent call last): File "E:/data/PrCharm/test1/55.py", line 3, in <module> list1.remove(list1) ValueError: list.remove(x): x not in list 我自己在我自己里面吗? False 5、Python列表的remove方法的注意事项 为何没有删除列表...
python list.remove(),del()和filter & lambda 面试题之中的一个。 下面代码能执行吗? l = [1,2,3,4,5] for i in range(0,len(l)): print i if l[i] % 2 == 0: del l[i] print l 结果: Traceback (most recent call last):...
>>> myList.index("revolves") 3 So we see that the corresponding index was displayed in the output. If some value is not found then an error is displayed. Here is an example : >>> myList.index("a") Traceback (most recent call last): ...
IndexError: list assignment index out of range >>> a.pop(7) Traceback (most recent call last): File "", line 1, in IndexError: pop index out of range 1. 2. 3. 4. 5. 6. 7. 8. 9. 10. 11. 12. 13. Python基础(中) ...
平时开发 Python 代码过程中,经常会遇到这个报错: ValueError:list.remove(x):xnotinlist 错误提示信息也很明确,就是移除的元素不在列表之中。 比如: >>>lst=[1,2,3]>>>lst.remove(4)Traceback(mostrecentcalllast):File"<stdin>",line1,in<module>ValueError:list.remove(x):xnotinlist ...
File"<stdin>", line1,in <module> ValueError: list.remove(x): xnotin list >>>del a[7] Traceback (most recent call last): File"<stdin>", line1,in <module> IndexError: list assignment index out of range >>> a.pop(7) Traceback (most recent call last): ...
Python Code: # Define a function 'remove_words' that removes specified words from a listdefremove_words(list1,remove_words):# Iterate through the elements in 'list1'forwordinlist(list1):# Check if the word is in the 'remove_words' listifwordinremove_words:# If it is, remove the wor...