Can you solve this real interview question? Remove All Adjacent Duplicates In String - You are given a string s consisting of lowercase English letters. A duplicate removal consists of choosing two adjacent and equal letters and removing them. We repeat
1047. Remove All Adjacent Duplicates In String # 题目 # Given a string S of lowercase letters, a duplicate removal consists of choosing two adjacent and equal letters, and removing them. We repeatedly make duplicate removals on S until we no longer can
1classSolution {2publicString removeDuplicates(String s,intk) {3StringBuilder sb =newStringBuilder(s);4Deque<Integer> stack =newArrayDeque<>();5for(inti = 0; i < sb.length(); i++) {6if(i == 0 || sb.charAt(i) != sb.charAt(i - 1)) {7stack.push(1);8}else{9intcount = st...
Return the final string after all such duplicate removals have been made. It is guaranteed the answer is unique. Example 1: Input:"abbaca" Output:"ca" Explanation: For example, in "abbaca" we could remove "bb" since the letters are adjacent and equal, and this is the only possible mov...
leetcode 1047. Remove All Adjacent Duplicates In String (python) 描述 Given a string S of lowercase letters, a duplicate removal consists of choosing two adjacent and equal letters, and removing them. W...leetcode 题号1047 Remove All Adjacent Duplicates In String 查看题目详情可点击此处。 题目...
The string entered here is“hello world” It is evident that ‘l’ and ‘o’ are repeated in the string. So, these two alphabets will be omitted out. The string after removing all the duplicates becomes: ‘helo wrd’ Thus, the different ways to do so in C programming are as follows:...
https://leetcode-cn.com/problems/remove-all-adjacent-duplicates-in-string/ 耗时 解题:38 min 题解:10 min 题意 给出由小写字母组成的字符串 S,重复项删除操作会选择两个相邻且相同的字母,并删除它们。 在S 上反复执行重复项删除操作,直到无法继续删除。 在完成所有重复项删除操作后返回最终的字符串。答案...
Solved: Hello, I have in a column, values including some duplicates : Ex : Input : ID Value ID1 A-B-A-C-A ID2 A-B ID3 A-C-C Expected Output : ID
Write a Java program to remove duplicates from a given stack.Sample Solution:Java Code:import java.util.Scanner; import java.util.HashSet; public class Stack { private int[] arr; private int top; // Constructor to initialize the stack public Stack(int size) { arr = new int[size]; top...
string removeDuplicates(string s, int k) { int i, streak; // streak will store count of consecutive duplicates while(1){ i = streak = 1; bool removed = false; streak = (s[i] == s[i - 1] ? streak + 1 : 1); if(streak == k) s.erase(i - k + 1, k), streak = 1, ...