Given a sorted array, remove the duplicates in place such that each element appear only once and return the new length. Do not allocate extra space for another array, you must do this in place with constant memory. For example, Given input array A = [1,1,2], Your function should retur...
Follow up for "Remove Duplicates": What if duplicates are allowed at mosttwice? For example, Given sorted arraynums=[1,1,1,2,2,3], Your function should return length =5, with the first five elements ofnumsbeing1,1,2,2and3. It doesn't matter what you leave beyond the new length. ...
19} Reference:http://www.programcreek.com/2013/01/leetcode-remove-duplicates-from-sorted-array-ii-java/
ArrayList<Integer>numbersList=newArrayList<>(Arrays.asList(1,1,2,3,3,3,4,5,6,6,6,7,8));LinkedHashSet<Integer>hashSet=newLinkedHashSet<>(items);ArrayList<Integer>listWithoutDuplicates=newArrayList<>(hashSet);System.out.println(listWithoutDuplicates);//[1, 2, 3, 4, 5, 6, 7, 8] Dr...
Given a sorted array nums, remove the duplicates in-place such that each element appear only once and return the new length. Do not allocate extra space for another array, you must do this by modifying the input array in-place with O(1) extra memory. ...
Map<Integer,Long>map=newHashMap<>();for(inti:numArray){if(map.containsKey(i)){//this element is in the map alreadymap.put(i,map.get(i)+1);}else{//found a new elementmap.put(i,1L);}} Now we can use theMapkeys and values to count duplicates, and even collect the duplicate and...
What if duplicates are allowed at most twice? For example, Given sorted array nums = [1,1,1,2,2,3], Your function should return length = 5, with the first five elements of nums being 1, 1, 2, 2 and 3. It doesn't matter what you leave beyond the new length. ...
We sort the array in the first step, which takes O(NlogN) time. After that, we execute the loop from 1 to n-1, which requires O(N) time. Therefore, this method’s worst-case time complexity for eliminating duplicates from the array is O(NlogN)+O(N)=O(NlogN). Auxiliary Space ...
publicclassSolution{publicintremoveDuplicates(int[]A){intcount=0;if(A==null||A.length==0){returncount;}count=1;// 从索引1开始遍历,获得不重复个数for(inti=1;i<A.length;i++){if(A[i]!=A[i-1]){count++;}}intuniqueIndex=1;// 记录已经有了多少个不重复的数字被换到了前面for(inti=1;...
26. Remove Duplicates from Sorted Array 给定一个有序的数组nums,删除重复内容,使每个元素只出现一次并返回新的长度。 不要为其他数组分配额外空间,您必须通过在O(1)额外内存中就地修改输入数组来实现此目的。 思路:数组有序,重复数组必定相邻! 其它和27是一样的。